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The settling velocity of inorganic particles of less than 0.1 mm dia., varies with the dia (d), in proportion to:
- a)d3
- b)d2
- c)d
- d)none of them, as dia does not affect the settling velocity
Correct answer is option 'B'. Can you explain this answer?
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The settling velocity of inorganic particles of less than 0.1 mm dia.,...
Settling velocity for particle size less than 0.1 mm,
Vs in mm/s,
d in mm
T temperature of water in °C,
Vs in mm/s,
d in mm
T temperature of water in °C,
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The settling velocity of inorganic particles of less than 0.1 mm dia.,...
Settling Velocity of Inorganic Particles
Settling velocity is the velocity at which particles settle down in a fluid under the influence of gravity. The settling velocity of inorganic particles of less than 0.1 mm dia varies with the diameter (d).
Proportionality with Diameter
The settling velocity of inorganic particles of less than 0.1 mm dia varies with the diameter (d) in proportion to d2. This means that the settling velocity increases with an increase in diameter.
Explanation
The settling velocity of particles is influenced by several factors such as particle size, shape, density, and viscosity of the fluid. The diameter of the particle is one of the primary factors that affect the settling velocity.
As the diameter of the particle increases, the gravitational force acting on the particle also increases. This leads to an increase in the settling velocity of the particle. The settling velocity is directly proportional to the square of the particle diameter (d2).
The settling velocity can be calculated using the Stokes' Law, which states that the settling velocity (Vs) is directly proportional to the square of the particle diameter (d2) and the density difference between the particle and the fluid (Δρ), and inversely proportional to the viscosity of the fluid (μ).
Vs = (2/9) * (d2) * (Δρ/μ)
Conclusion
In conclusion, the settling velocity of inorganic particles of less than 0.1 mm dia varies with the diameter (d) in proportion to d2. An increase in the diameter of the particle leads to an increase in the settling velocity. This relationship is described by the Stokes' Law, which can be used to calculate the settling velocity of particles in a fluid.
Settling velocity is the velocity at which particles settle down in a fluid under the influence of gravity. The settling velocity of inorganic particles of less than 0.1 mm dia varies with the diameter (d).
Proportionality with Diameter
The settling velocity of inorganic particles of less than 0.1 mm dia varies with the diameter (d) in proportion to d2. This means that the settling velocity increases with an increase in diameter.
Explanation
The settling velocity of particles is influenced by several factors such as particle size, shape, density, and viscosity of the fluid. The diameter of the particle is one of the primary factors that affect the settling velocity.
As the diameter of the particle increases, the gravitational force acting on the particle also increases. This leads to an increase in the settling velocity of the particle. The settling velocity is directly proportional to the square of the particle diameter (d2).
The settling velocity can be calculated using the Stokes' Law, which states that the settling velocity (Vs) is directly proportional to the square of the particle diameter (d2) and the density difference between the particle and the fluid (Δρ), and inversely proportional to the viscosity of the fluid (μ).
Vs = (2/9) * (d2) * (Δρ/μ)
Conclusion
In conclusion, the settling velocity of inorganic particles of less than 0.1 mm dia varies with the diameter (d) in proportion to d2. An increase in the diameter of the particle leads to an increase in the settling velocity. This relationship is described by the Stokes' Law, which can be used to calculate the settling velocity of particles in a fluid.
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The settling velocity of inorganic particles of less than 0.1 mm dia., varies with the dia (d), in proportion to:a)d3b)d2c)dd)none of them, as dia does not affect the settling velocityCorrect answer is option 'B'. Can you explain this answer?
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