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Enol isomer of which of the following forms six membered stable ring through intramolecular H-bonding?
  • a)
    Nitroethanal
  • b)
    Cyanoethanal
  • c)
    2,4-pentanedione
  • d)
    2-oxocyclohexane carbaldehyde 
Correct answer is option 'C,D'. Can you explain this answer?
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Enol isomer of which of the following forms six membered stable ring t...
Enol Isomers and Intramolecular H-Bonding

Enol isomers are a type of tautomers, which are isomers that differ in the position of a proton and a double bond. Enol isomers have a hydroxyl (-OH) group and a double bond (-C=C-) in their structure. The keto form of enol isomers has a carbonyl (-C=O) group instead of the hydroxyl group.

Intramolecular hydrogen bonding is a type of hydrogen bonding that occurs within a molecule. It involves the interaction between a hydrogen atom and an electronegative atom (such as oxygen or nitrogen) in the same molecule. Intramolecular hydrogen bonding can lead to the formation of stable rings in molecules.

Six-Membered Stable Ring Formation

Among the given options, two molecules can form a stable six-membered ring through intramolecular hydrogen bonding:

1. 2,4-Pentanedione

2,4-Pentanedione is a molecule that contains two carbonyl groups and a methyl group. Its enol form has a hydroxyl group (-OH) and a double bond (-C=C-) between the second and third carbon atoms. Intramolecular hydrogen bonding can occur between the hydroxyl group and the carbonyl group on the fourth carbon atom, resulting in the formation of a stable six-membered ring.

2. 2-Oxocyclohexanecarbaldehyde

2-Oxocyclohexanecarbaldehyde is a molecule that contains a cyclohexane ring, a carbonyl group, and an aldehyde group. Its enol form has a hydroxyl group (-OH) and a double bond (-C=C-) between the first and second carbon atoms of the cyclohexane ring. Intramolecular hydrogen bonding can occur between the hydroxyl group and the carbonyl group, resulting in the formation of a stable six-membered ring.

Therefore, the correct answer is option C and D.
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Enol isomer of which of the following forms six membered stable ring t...
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Enol isomer of which of the following forms six membered stable ring through intramolecular H-bonding?a)Nitroethanalb)Cyanoethanalc)2,4-pentanedioned)2-oxocyclohexane carbaldehydeCorrect answer is option 'C,D'. Can you explain this answer?
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Enol isomer of which of the following forms six membered stable ring through intramolecular H-bonding?a)Nitroethanalb)Cyanoethanalc)2,4-pentanedioned)2-oxocyclohexane carbaldehydeCorrect answer is option 'C,D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Enol isomer of which of the following forms six membered stable ring through intramolecular H-bonding?a)Nitroethanalb)Cyanoethanalc)2,4-pentanedioned)2-oxocyclohexane carbaldehydeCorrect answer is option 'C,D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Enol isomer of which of the following forms six membered stable ring through intramolecular H-bonding?a)Nitroethanalb)Cyanoethanalc)2,4-pentanedioned)2-oxocyclohexane carbaldehydeCorrect answer is option 'C,D'. Can you explain this answer?.
Solutions for Enol isomer of which of the following forms six membered stable ring through intramolecular H-bonding?a)Nitroethanalb)Cyanoethanalc)2,4-pentanedioned)2-oxocyclohexane carbaldehydeCorrect answer is option 'C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
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