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An ammeter or range 5A is to be converted into an ammeter of range 10v. If the resistance of ammeter be 0.1ohm,then what resistance should be converted in series with it?
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An ammeter or range 5A is to be converted into an ammeter of range 10v...
**Conversion of an Ammeter into a Voltmeter**

To convert an ammeter into a voltmeter, a suitable resistor is added in series with the ammeter. This resistor is known as a shunt resistor. The shunt resistor diverts a portion of the current away from the ammeter, allowing it to measure voltage across the resistor.

**Understanding the Problem**

In this problem, we are given an ammeter with a range of 5A, and we need to convert it into a voltmeter with a range of 10V. The resistance of the ammeter is given as 0.1 ohm. We need to determine the resistance of the shunt resistor that should be connected in series with the ammeter.

**Solution**

To solve this problem, we can use the principle of current division. According to this principle, the current passing through each resistor in a parallel circuit is inversely proportional to its resistance.

We can start by calculating the current passing through the ammeter when a maximum voltage of 10V is applied. Using Ohm's Law (V = IR), we can calculate the current using the resistance of the ammeter:

I = V / R
I = 10V / 0.1Ω
I = 100A

The current passing through the ammeter is 100A. Since the ammeter has a range of 5A, we need to divert 95A away from the ammeter using the shunt resistor.

Using the principle of current division, we can calculate the resistance of the shunt resistor:

Rshunt = Rammeter * (Iammeter / Ishunt)
Rshunt = 0.1Ω * (5A / 95A)
Rshunt = 0.1Ω * 0.0526
Rshunt ≈ 0.00526Ω

Therefore, a shunt resistor with a resistance of approximately 0.00526 ohm should be connected in series with the ammeter to convert it into a voltmeter with a range of 10V.

**Conclusion**

To convert an ammeter into a voltmeter with a specific range, a shunt resistor should be connected in series with the ammeter. By using the principle of current division, we can determine the resistance of the shunt resistor required for the conversion. In this problem, the ammeter with a range of 5A was converted into a voltmeter with a range of 10V by adding a shunt resistor with a resistance of approximately 0.00526 ohm.
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An ammeter or range 5A is to be converted into an ammeter of range 10v...
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Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.How shunt is connected with a ammeter?

Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.What will be the value of the shunt resistance if the ammeter coil resistance is 1Ω and multiplying power is 100?

Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.Current through shunt is

An ammeter or range 5A is to be converted into an ammeter of range 10v. If the resistance of ammeter be 0.1ohm,then what resistance should be converted in series with it?
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An ammeter or range 5A is to be converted into an ammeter of range 10v. If the resistance of ammeter be 0.1ohm,then what resistance should be converted in series with it? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An ammeter or range 5A is to be converted into an ammeter of range 10v. If the resistance of ammeter be 0.1ohm,then what resistance should be converted in series with it? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An ammeter or range 5A is to be converted into an ammeter of range 10v. If the resistance of ammeter be 0.1ohm,then what resistance should be converted in series with it?.
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