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What is the instantaneous sol-air temperature for a wall with the following conditoins?
Total of direct and diffuse solar radiation: 250 W/m2
Absorptivity of surface : 0.8
Outside surface heat-transfer coefficient:
25 W/m2K
Outside air temperature : 35°C
Total of direct and diffuse solar radiation: 250 W/m2
Absorptivity of surface : 0.8
Outside surface heat-transfer coefficient:
25 W/m2K
Outside air temperature : 35°C
- a)40°C
- b)43°C
- c)49°C
- d)39°C
Correct answer is option 'B'. Can you explain this answer?
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What is the instantaneous sol-air temperature for a wall with the foll...
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To calculate the instantaneous sol-air temperature of the wall, we need to consider the heat transfer between the wall and the surroundings.
The heat transfer through the wall can be calculated using the following equation:
Q = U * A * (Ts - Ta)
Where:
Q is the heat transfer rate (W)
U is the overall heat transfer coefficient (W/m^2K)
A is the surface area of the wall (m^2)
Ts is the surface temperature of the wall (sol-air temperature) (°C)
Ta is the outside air temperature (°C)
Rearranging the equation, we can solve for Ts:
Ts = (Q / (U * A)) + Ta
Given:
Total of direct and diffuse solar radiation = 250 W/m^2
Absorptivity of surface = 0.8
Outside surface heat-transfer coefficient = 25 W/m^2K
Outside air temperature = 35 °C
Assuming the surface area of the wall is 1 m^2, we can substitute the values into the equation:
Q = 250 W/m^2 * 0.8 = 200 W/m^2
U = 25 W/m^2K
A = 1 m^2
Ta = 35 °C
Ts = (200 W/m^2 / (25 W/m^2K * 1 m^2)) + 35 °C
Ts = 8 °C + 35 °C
Ts = 43 °C
Therefore, the instantaneous sol-air temperature for the wall is 43 °C.
The heat transfer through the wall can be calculated using the following equation:
Q = U * A * (Ts - Ta)
Where:
Q is the heat transfer rate (W)
U is the overall heat transfer coefficient (W/m^2K)
A is the surface area of the wall (m^2)
Ts is the surface temperature of the wall (sol-air temperature) (°C)
Ta is the outside air temperature (°C)
Rearranging the equation, we can solve for Ts:
Ts = (Q / (U * A)) + Ta
Given:
Total of direct and diffuse solar radiation = 250 W/m^2
Absorptivity of surface = 0.8
Outside surface heat-transfer coefficient = 25 W/m^2K
Outside air temperature = 35 °C
Assuming the surface area of the wall is 1 m^2, we can substitute the values into the equation:
Q = 250 W/m^2 * 0.8 = 200 W/m^2
U = 25 W/m^2K
A = 1 m^2
Ta = 35 °C
Ts = (200 W/m^2 / (25 W/m^2K * 1 m^2)) + 35 °C
Ts = 8 °C + 35 °C
Ts = 43 °C
Therefore, the instantaneous sol-air temperature for the wall is 43 °C.
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What is the instantaneous sol-air temperature for a wall with the following conditoins?Total of direct and diffuse solar radiation: 250 W/m2Absorptivity of surface : 0.8Outside surface heat-transfer coefficient:25 W/m2KOutside air temperature : 35°Ca)40°Cb)43°Cc)49°Cd)39°CCorrect answer is option 'B'. Can you explain this answer?
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