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The solution of differential equation dy = (1-y) dx is
  • a)
    y = e-x c
  • b)
    y = ex c
  • c)
    y = 1 ce-x
  • d)
    y = 1 cex
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The solution of differential equation dy = (1-y) dx isa)y = e-x cb)y...
dy = (1 – y) dx
y = 1 ce-x
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Most Upvoted Answer
The solution of differential equation dy = (1-y) dx isa)y = e-x cb)y...
Understanding the Differential Equation
The given differential equation is:
dy = (1 - y) dx
This means we can rearrange it to find the relationship between y and x.
Rearranging the Equation
We can rewrite the equation as:
dy / (1 - y) = dx
This format allows us to separate variables, making it easier to integrate both sides.
Integrating Both Sides
Now, integrate both sides:
∫ dy / (1 - y) = ∫ dx
The left side integrates to -ln|1 - y|, and the right side integrates to x + C, where C is the integration constant. Thus, we have:
-ln|1 - y| = x + C
Solving for y
To solve for y, we exponentiate both sides:
|1 - y| = e^(-x - C)
This simplifies to:
1 - y = ±e^(-x - C)
Now isolate y:
y = 1 - ±e^(-x - C)
By setting a new constant K = ±e^(-C), we can express y as:
y = 1 - Ke^(-x)
Analyzing the Solutions
The form y = 1 - Ke^(-x) indicates that as x approaches infinity, y approaches 1 (the horizontal asymptote). Therefore, the solution of this differential equation approaches the line y = 1.
Conclusion
Thus, the correct answer is indeed option 'C', which indicates that the solution converges to the constant value:
y = 1.
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Community Answer
The solution of differential equation dy = (1-y) dx isa)y = e-x cb)y...
dy = (1 – y) dx
y = 1 ce-x
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The solution of differential equation dy = (1-y) dx isa)y = e-x cb)y = ex cc)y = 1 ce-xd)y = 1 cexCorrect answer is option 'C'. Can you explain this answer?
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