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An odd shaped body weighing 7.5 kg and occupying 0.01 m3 volume wiil be completely submerged in a fluid having specific gravity of
- a)1
- b)1.2
- c)0.8
- d)0.75
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
An odd shaped body weighing 7.5 kg and occupying 0.01 m3 volume wiil b...
Submergence of Odd Shaped Body in Fluid
Given:
Weight of the body, W = 7.5 kg
Volume of the body, V = 0.01 m3
Specific gravity of the fluid, S.G. = ρ/ρw
where, ρ = Density of the fluid
ρw = Density of water
a) If S.G. = 1
Density of water, ρw = 1000 kg/m3
Weight of the displaced water, WD = V × ρw = 0.01 × 1000 = 10 kg
As the weight of the body (7.5 kg) is less than the weight of the displaced water (10 kg), the body will float on the surface of the fluid. Therefore, the answer is incorrect.
b) If S.G. = 1.2
Density of the fluid, ρ = S.G. × ρw = 1.2 × 1000 = 1200 kg/m3
Weight of the displaced water, WD = V × ρw = 0.01 × 1000 = 10 kg
Buoyancy force acting on the body, FB = WD × g = 10 × 9.81 = 98.1 N
Weight of the body, W = 7.5 × 9.81 = 73.58 N
As the buoyancy force (98.1 N) is greater than the weight of the body (73.58 N), the body will float on the surface of the fluid. Therefore, the answer is incorrect.
c) If S.G. = 0.8
Density of the fluid, ρ = S.G. × ρw = 0.8 × 1000 = 800 kg/m3
Weight of the displaced water, WD = V × ρw = 0.01 × 1000 = 10 kg
Buoyancy force acting on the body, FB = WD × g = 10 × 9.81 = 98.1 N
Weight of the body, W = 7.5 × 9.81 = 73.58 N
As the buoyancy force (98.1 N) is greater than the weight of the body (73.58 N), the body will float on the surface of the fluid. Therefore, the answer is incorrect.
d) If S.G. = 0.75
Density of the fluid, ρ = S.G. × ρw = 0.75 × 1000 = 750 kg/m3
Weight of the displaced water, WD = V × ρw = 0.01 × 1000 = 10 kg
Buoyancy force acting on the body, FB = WD × g = 10 × 9.81 = 98.1 N
Weight of the body, W = 7.5 × 9.81 = 73.58 N
As the buoyancy force (98.1 N) is greater than the weight of the body (73.58 N), the body will sink and be completely submerged in the fluid. Therefore, the correct answer is option 'D'.
Given:
Weight of the body, W = 7.5 kg
Volume of the body, V = 0.01 m3
Specific gravity of the fluid, S.G. = ρ/ρw
where, ρ = Density of the fluid
ρw = Density of water
a) If S.G. = 1
Density of water, ρw = 1000 kg/m3
Weight of the displaced water, WD = V × ρw = 0.01 × 1000 = 10 kg
As the weight of the body (7.5 kg) is less than the weight of the displaced water (10 kg), the body will float on the surface of the fluid. Therefore, the answer is incorrect.
b) If S.G. = 1.2
Density of the fluid, ρ = S.G. × ρw = 1.2 × 1000 = 1200 kg/m3
Weight of the displaced water, WD = V × ρw = 0.01 × 1000 = 10 kg
Buoyancy force acting on the body, FB = WD × g = 10 × 9.81 = 98.1 N
Weight of the body, W = 7.5 × 9.81 = 73.58 N
As the buoyancy force (98.1 N) is greater than the weight of the body (73.58 N), the body will float on the surface of the fluid. Therefore, the answer is incorrect.
c) If S.G. = 0.8
Density of the fluid, ρ = S.G. × ρw = 0.8 × 1000 = 800 kg/m3
Weight of the displaced water, WD = V × ρw = 0.01 × 1000 = 10 kg
Buoyancy force acting on the body, FB = WD × g = 10 × 9.81 = 98.1 N
Weight of the body, W = 7.5 × 9.81 = 73.58 N
As the buoyancy force (98.1 N) is greater than the weight of the body (73.58 N), the body will float on the surface of the fluid. Therefore, the answer is incorrect.
d) If S.G. = 0.75
Density of the fluid, ρ = S.G. × ρw = 0.75 × 1000 = 750 kg/m3
Weight of the displaced water, WD = V × ρw = 0.01 × 1000 = 10 kg
Buoyancy force acting on the body, FB = WD × g = 10 × 9.81 = 98.1 N
Weight of the body, W = 7.5 × 9.81 = 73.58 N
As the buoyancy force (98.1 N) is greater than the weight of the body (73.58 N), the body will sink and be completely submerged in the fluid. Therefore, the correct answer is option 'D'.
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Community Answer
An odd shaped body weighing 7.5 kg and occupying 0.01 m3 volume wiil b...
Given M = 7.5 kg
and V = 0.01 m^3
Now Density of body, p = 7.5 / 0.01 = 750 kg/m^3
and now
Sp. gravity = p of body / p of standard fluid
= 750 / 1000 = 0.75
and V = 0.01 m^3
Now Density of body, p = 7.5 / 0.01 = 750 kg/m^3
and now
Sp. gravity = p of body / p of standard fluid
= 750 / 1000 = 0.75
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An odd shaped body weighing 7.5 kg and occupying 0.01 m3 volume wiil be completely submerged in a fluid having specific gravity ofa)1b)1.2c)0.8d)0.75Correct answer is option 'D'. Can you explain this answer?
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An odd shaped body weighing 7.5 kg and occupying 0.01 m3 volume wiil be completely submerged in a fluid having specific gravity ofa)1b)1.2c)0.8d)0.75Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about An odd shaped body weighing 7.5 kg and occupying 0.01 m3 volume wiil be completely submerged in a fluid having specific gravity ofa)1b)1.2c)0.8d)0.75Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An odd shaped body weighing 7.5 kg and occupying 0.01 m3 volume wiil be completely submerged in a fluid having specific gravity ofa)1b)1.2c)0.8d)0.75Correct answer is option 'D'. Can you explain this answer?.
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