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The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will be
- a)4
- b)7
- c)12
- d)15
Correct answer is option 'D'. Can you explain this answer?
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The number of intensity minima in the Fraunhofer diffraction pattern of a single slit is given by the formula:
N = (2W/λ)sinθ
Where W is the width of the slit, λ is the wavelength of the light, and θ is the angle between the direction of the incident light and the direction of the diffracted light.
For a single slit with a width of 10 μm and a wavelength of 500 nm (corresponding to green light), the maximum number of intensity minima can be calculated as follows:
N = (2 × 10 μm / 500 nm)sinθ
The sine function has a maximum value of 1, so the maximum number of intensity minima occurs when sinθ = 1. Therefore:
N = (2 × 10 μm / 500 nm) × 1
N = 80
Therefore, the maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit with a width of 10 μm and a wavelength of 500 nm is 80.
N = (2W/λ)sinθ
Where W is the width of the slit, λ is the wavelength of the light, and θ is the angle between the direction of the incident light and the direction of the diffracted light.
For a single slit with a width of 10 μm and a wavelength of 500 nm (corresponding to green light), the maximum number of intensity minima can be calculated as follows:
N = (2 × 10 μm / 500 nm)sinθ
The sine function has a maximum value of 1, so the maximum number of intensity minima occurs when sinθ = 1. Therefore:
N = (2 × 10 μm / 500 nm) × 1
N = 80
Therefore, the maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit with a width of 10 μm and a wavelength of 500 nm is 80.
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The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will bea)4b)7c)12d)15Correct answer is option 'D'. Can you explain this answer?
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The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will bea)4b)7c)12d)15Correct answer is option 'D'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will bea)4b)7c)12d)15Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will bea)4b)7c)12d)15Correct answer is option 'D'. Can you explain this answer?.
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