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Composite wire of uniform diameter 3.0 mm consisting of A copper wire of length 2.2 m and a steel wire of length 7.6 status under load by 0.7 mm calculate the load given that young modulus of copper is 1.1×10 ki power 11 Pascal for the Steel 2.0×10 ki power 11 Pascal?
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Composite wire of uniform diameter 3.0 mm consisting of A copper wire ...
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Composite wire of uniform diameter 3.0 mm consisting of A copper wire ...
Given data:
- Diameter of composite wire (d) = 3.0 mm
- Length of copper wire (Lc) = 2.2 m
- Length of steel wire (Ls) = 7.6 m
- Elongation of composite wire (ΔL) = 0.7 mm
- Young's modulus of copper (Ec) = 1.1 × 10^11 Pa
- Young's modulus of steel (Es) = 2.0 × 10^11 Pa
Calculating cross-sectional area of composite wire:
- The diameter of the composite wire is given as 3.0 mm.
- We know that the diameter is twice the radius (r), so the radius of the composite wire is 1.5 mm or 0.0015 m.
- The cross-sectional area (A) of the composite wire can be calculated using the formula A = πr^2.
- Substituting the value of the radius, we get A = π(0.0015)^2 = 7.065 × 10^-6 m^2.
Calculating total elongation:
- The total elongation (ΔL) of the composite wire is given as 0.7 mm or 0.0007 m.
- The total elongation is the sum of the elongations of the copper and steel wires, ΔL = ΔLc + ΔLs.
Calculating elongation of copper wire:
- The elongation of a wire can be calculated using the formula ΔL = FL/AE, where F is the force applied, A is the cross-sectional area, and E is the Young's modulus.
- Rearranging the formula, we get F = ΔL × A × E.
- Substituting the values, we get Fc = (0.0007) × (7.065 × 10^-6) × (1.1 × 10^11) = 0.005415 N.
Calculating elongation of steel wire:
- Similarly, we can calculate the elongation of the steel wire using the same formula.
- Fs = (0.0007) × (7.065 × 10^-6) × (2.0 × 10^11) = 0.01083 N.
Calculating total load:
- The total load is the sum of the loads on the copper and steel wires, Ft = Fc + Fs.
- Substituting the values, we get Ft = 0.005415 N + 0.01083 N = 0.016245 N.
Answer:
The load on the composite wire is approximately 0.016245 N.
- Diameter of composite wire (d) = 3.0 mm
- Length of copper wire (Lc) = 2.2 m
- Length of steel wire (Ls) = 7.6 m
- Elongation of composite wire (ΔL) = 0.7 mm
- Young's modulus of copper (Ec) = 1.1 × 10^11 Pa
- Young's modulus of steel (Es) = 2.0 × 10^11 Pa
Calculating cross-sectional area of composite wire:
- The diameter of the composite wire is given as 3.0 mm.
- We know that the diameter is twice the radius (r), so the radius of the composite wire is 1.5 mm or 0.0015 m.
- The cross-sectional area (A) of the composite wire can be calculated using the formula A = πr^2.
- Substituting the value of the radius, we get A = π(0.0015)^2 = 7.065 × 10^-6 m^2.
Calculating total elongation:
- The total elongation (ΔL) of the composite wire is given as 0.7 mm or 0.0007 m.
- The total elongation is the sum of the elongations of the copper and steel wires, ΔL = ΔLc + ΔLs.
Calculating elongation of copper wire:
- The elongation of a wire can be calculated using the formula ΔL = FL/AE, where F is the force applied, A is the cross-sectional area, and E is the Young's modulus.
- Rearranging the formula, we get F = ΔL × A × E.
- Substituting the values, we get Fc = (0.0007) × (7.065 × 10^-6) × (1.1 × 10^11) = 0.005415 N.
Calculating elongation of steel wire:
- Similarly, we can calculate the elongation of the steel wire using the same formula.
- Fs = (0.0007) × (7.065 × 10^-6) × (2.0 × 10^11) = 0.01083 N.
Calculating total load:
- The total load is the sum of the loads on the copper and steel wires, Ft = Fc + Fs.
- Substituting the values, we get Ft = 0.005415 N + 0.01083 N = 0.016245 N.
Answer:
The load on the composite wire is approximately 0.016245 N.
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Composite wire of uniform diameter 3.0 mm consisting of A copper wire of length 2.2 m and a steel wire of length 7.6 status under load by 0.7 mm calculate the load given that young modulus of copper is 1.1×10 ki power 11 Pascal for the Steel 2.0×10 ki power 11 Pascal?
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Composite wire of uniform diameter 3.0 mm consisting of A copper wire of length 2.2 m and a steel wire of length 7.6 status under load by 0.7 mm calculate the load given that young modulus of copper is 1.1×10 ki power 11 Pascal for the Steel 2.0×10 ki power 11 Pascal? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Composite wire of uniform diameter 3.0 mm consisting of A copper wire of length 2.2 m and a steel wire of length 7.6 status under load by 0.7 mm calculate the load given that young modulus of copper is 1.1×10 ki power 11 Pascal for the Steel 2.0×10 ki power 11 Pascal? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Composite wire of uniform diameter 3.0 mm consisting of A copper wire of length 2.2 m and a steel wire of length 7.6 status under load by 0.7 mm calculate the load given that young modulus of copper is 1.1×10 ki power 11 Pascal for the Steel 2.0×10 ki power 11 Pascal?.
Composite wire of uniform diameter 3.0 mm consisting of A copper wire of length 2.2 m and a steel wire of length 7.6 status under load by 0.7 mm calculate the load given that young modulus of copper is 1.1×10 ki power 11 Pascal for the Steel 2.0×10 ki power 11 Pascal? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Composite wire of uniform diameter 3.0 mm consisting of A copper wire of length 2.2 m and a steel wire of length 7.6 status under load by 0.7 mm calculate the load given that young modulus of copper is 1.1×10 ki power 11 Pascal for the Steel 2.0×10 ki power 11 Pascal? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Composite wire of uniform diameter 3.0 mm consisting of A copper wire of length 2.2 m and a steel wire of length 7.6 status under load by 0.7 mm calculate the load given that young modulus of copper is 1.1×10 ki power 11 Pascal for the Steel 2.0×10 ki power 11 Pascal?.
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Composite wire of uniform diameter 3.0 mm consisting of A copper wire of length 2.2 m and a steel wire of length 7.6 status under load by 0.7 mm calculate the load given that young modulus of copper is 1.1×10 ki power 11 Pascal for the Steel 2.0×10 ki power 11 Pascal?, a detailed solution for Composite wire of uniform diameter 3.0 mm consisting of A copper wire of length 2.2 m and a steel wire of length 7.6 status under load by 0.7 mm calculate the load given that young modulus of copper is 1.1×10 ki power 11 Pascal for the Steel 2.0×10 ki power 11 Pascal? has been provided alongside types of Composite wire of uniform diameter 3.0 mm consisting of A copper wire of length 2.2 m and a steel wire of length 7.6 status under load by 0.7 mm calculate the load given that young modulus of copper is 1.1×10 ki power 11 Pascal for the Steel 2.0×10 ki power 11 Pascal? theory, EduRev gives you an
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