A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mandomega;2A2 andminus;d)The total energy of the system is 1/2mandomega;2A2 +Correct answer is option 'D'. Can you explain this answer?

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a)
The new equilibrium position is at a distance 2qE/K from x = 0
b)
The new equilibrium position is at a distance qE/2K from x = 0
c)
The total energy of the system is 1/2 mω²A² −
d)
The total energy of the system is 1/2 mω²A² +

Correct answer is option 'D'. Can you explain this answer?

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A body of mass M and charge q is connected to a spring of spring const...

Energy at the extreme
= 1/2 kA² = T. E
After switching on electric field
New mean position ⟹ kx_o = qE
x_o = qE/k
So entreme position also shifts by qE/k

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A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer?

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A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer?.

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