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A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer?.

Solutions for A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A body of mass M and charge q is connected to a spring of spring constant k. It is oscillating along xdirection about its equilibrium position, taken to be at x = 0, with an amplitude A. An electric field E is applied along the x-direction. Which of the following statements is correct?a)The new equilibrium position is at a distance 2qE/Kfrom x = 0b)The new equilibrium position is at a distance qE/2Kfrom x = 0c)The total energy of the system is 1/2mω2A2 −d)The total energy of the system is 1/2mω2A2 +Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.