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For a fluid having Prandtl number equal to unity how are the hydrodynamic boundary layer thickness δ and the thermal boundary layer thickness δt related
- a)δ = δt
- b)δ > δt
- c)δ < δt
- d)δt = δ1/3
Correct answer is option 'A'. Can you explain this answer?
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For a fluid having Prandtl number equal to unity how are the hydrodyna...
Where,
δt = Thickness of Thermal boundary layer
δ = Thickness of hydrodynamic boundary layer
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For a fluid having Prandtl number equal to unity how are the hydrodyna...
And thermal boundary layer thickness related?
For a fluid with a Prandtl number equal to unity, the hydrodynamic boundary layer thickness and thermal boundary layer thickness are equal. This means that the thickness of the layer of fluid near a solid surface where the flow is influenced by viscous effects (hydrodynamic boundary layer) is the same as the thickness of the layer of fluid where the heat transfer is influenced by thermal effects (thermal boundary layer). The Prandtl number (Pr) is the ratio of momentum diffusivity to thermal diffusivity, and when it is equal to unity, it indicates that the fluid has similar rates of momentum and heat transfer. As a result, the boundary layer thicknesses for both hydrodynamics and thermal effects are equal.
For a fluid with a Prandtl number equal to unity, the hydrodynamic boundary layer thickness and thermal boundary layer thickness are equal. This means that the thickness of the layer of fluid near a solid surface where the flow is influenced by viscous effects (hydrodynamic boundary layer) is the same as the thickness of the layer of fluid where the heat transfer is influenced by thermal effects (thermal boundary layer). The Prandtl number (Pr) is the ratio of momentum diffusivity to thermal diffusivity, and when it is equal to unity, it indicates that the fluid has similar rates of momentum and heat transfer. As a result, the boundary layer thicknesses for both hydrodynamics and thermal effects are equal.
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For a fluid having Prandtl number equal to unity how are the hydrodynamic boundary layer thickness δ and the thermal boundary layer thickness δtrelateda)δ = δtb)δ >δtc)δ <δtd)δt =δ1/3Correct answer is option 'A'. Can you explain this answer?
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