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If the length of the cantilever beam is halved, then natural frequency of the mass M at the end of this cantilever beam of negligible mass is increased by a factor of
  • a)
    2
  • b)
    4
  • c)
  • d)
    8
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If the length of the cantilever beam is halved, then natural frequency...
Deflection of a cantilever beam with Point load = (WL^3)/3EI=∆
Natural frequency = wn= √(g/∆)
Here when L=L/2
then deflection=(WL^3)/3EI*(1/8)=∆/8
Natural frequency=wn*=√(g÷∆/8)=√(8g/∆) = √8 * wn
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