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A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:
- a)772 J
- b)2520 J
- c)2100 J
- d)420 J
Correct answer is option 'D'. Can you explain this answer?
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A Carnot's engine works as a refrigerator between 250 K and 300 K....
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A Carnot's engine works as a refrigerator between 250 K and 300 K....
To determine the amount of work done in each cycle to operate the refrigerator, we need to use the Carnot efficiency formula. The Carnot efficiency is given by the equation:
Efficiency = 1 - (Tc/Th)
Where Tc is the absolute temperature of the cold reservoir and Th is the absolute temperature of the hot reservoir.
- Given values:
The cold reservoir temperature (Tc) = 250 K
The hot reservoir temperature (Th) = 300 K
- Calculating the Carnot efficiency:
Efficiency = 1 - (250/300)
Efficiency = 1 - 0.8333
Efficiency = 0.1667
This means that the Carnot engine can convert only 16.67% of the input heat into work.
- Determining the work done:
The amount of heat received by the refrigerator from the cold reservoir is given as 500 cal.
- Converting heat to joules:
1 calorie = 4.184 joules
Therefore, 500 cal = 500 * 4.184 J = 2092 J
- Calculating work done:
Work done = Efficiency * Heat received
Work done = 0.1667 * 2092 J
Work done = 348.67 J
Therefore, the work done in each cycle to operate the refrigerator is approximately 348.67 J.
However, the correct option provided is 420 J, which is not the same as the calculated value. It is possible that there is an error in the given answer options or in the calculation provided. Please double-check the answer options or consider recalculating the values to ensure accuracy.
Efficiency = 1 - (Tc/Th)
Where Tc is the absolute temperature of the cold reservoir and Th is the absolute temperature of the hot reservoir.
- Given values:
The cold reservoir temperature (Tc) = 250 K
The hot reservoir temperature (Th) = 300 K
- Calculating the Carnot efficiency:
Efficiency = 1 - (250/300)
Efficiency = 1 - 0.8333
Efficiency = 0.1667
This means that the Carnot engine can convert only 16.67% of the input heat into work.
- Determining the work done:
The amount of heat received by the refrigerator from the cold reservoir is given as 500 cal.
- Converting heat to joules:
1 calorie = 4.184 joules
Therefore, 500 cal = 500 * 4.184 J = 2092 J
- Calculating work done:
Work done = Efficiency * Heat received
Work done = 0.1667 * 2092 J
Work done = 348.67 J
Therefore, the work done in each cycle to operate the refrigerator is approximately 348.67 J.
However, the correct option provided is 420 J, which is not the same as the calculated value. It is possible that there is an error in the given answer options or in the calculation provided. Please double-check the answer options or consider recalculating the values to ensure accuracy.
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A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:a)772 Jb)2520 Jc)2100 Jd)420 JCorrect answer is option 'D'. Can you explain this answer?
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A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:a)772 Jb)2520 Jc)2100 Jd)420 JCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:a)772 Jb)2520 Jc)2100 Jd)420 JCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:a)772 Jb)2520 Jc)2100 Jd)420 JCorrect answer is option 'D'. Can you explain this answer?.
A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:a)772 Jb)2520 Jc)2100 Jd)420 JCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:a)772 Jb)2520 Jc)2100 Jd)420 JCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:a)772 Jb)2520 Jc)2100 Jd)420 JCorrect answer is option 'D'. Can you explain this answer?.
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A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:a)772 Jb)2520 Jc)2100 Jd)420 JCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:a)772 Jb)2520 Jc)2100 Jd)420 JCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is:a)772 Jb)2520 Jc)2100 Jd)420 JCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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