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If β is one of the angles between the normals to the ellipse, x2 + 3y2 = 9 at the points (3 cosθ, √3 sinθ)and(−3 sin θ√3 cosθ) ′; θϵ (0, π/2) ; then 2 cot β /sin 2θ is equal to:
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If β is one of the angles between the normals to the ellipse, x2 ...
Just find the eqns of normals at the given point and use the formula tanθ = |m1-m2|/|(1+m1*m2)| for the angle between the normals. In the process sin2θ will cancel out.
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If β is one of the angles between the normals to the ellipse, x2 + 3y2 = 9 at the points (3 cosθ, √3 sinθ)and(−3 sin θ√3 cosθ) ′; θϵ (0, π/2) ; then 2 cot β /sin 2θ is equal to:a)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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