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Two parabolas with a common vertex and with axes along x-axis and y-axis, respectively, intersect each other in the first quadrant. If the length of the latus rectum of each parabola is 3, then the equation of  the common tangent to the two parabolas is :
  • a)
    8(2x + y) + 3 = 0
  • b)
    3(x + y) + 4 = 0
  • c)
    4(x + y) + 3 = 0
  • d)
    x + 2y + 3 = 0
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Two parabolas with a common vertex and with axes along x-axis and y-ax...



4y = −4x − 3
4(x + y) + 3 = 0
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Two parabolas with a common vertex and with axes along x-axis and y-axis, respectively, intersect each other in the first quadrant. If the length of the latus rectum of each parabola is 3, then the equation of the common tangent to the two parabolas is :a)8(2x + y) + 3 = 0b)3(x + y) + 4 = 0c)4(x + y) + 3 = 0d)x + 2y + 3 = 0Correct answer is option 'C'. Can you explain this answer?
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Two parabolas with a common vertex and with axes along x-axis and y-axis, respectively, intersect each other in the first quadrant. If the length of the latus rectum of each parabola is 3, then the equation of the common tangent to the two parabolas is :a)8(2x + y) + 3 = 0b)3(x + y) + 4 = 0c)4(x + y) + 3 = 0d)x + 2y + 3 = 0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two parabolas with a common vertex and with axes along x-axis and y-axis, respectively, intersect each other in the first quadrant. If the length of the latus rectum of each parabola is 3, then the equation of the common tangent to the two parabolas is :a)8(2x + y) + 3 = 0b)3(x + y) + 4 = 0c)4(x + y) + 3 = 0d)x + 2y + 3 = 0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two parabolas with a common vertex and with axes along x-axis and y-axis, respectively, intersect each other in the first quadrant. If the length of the latus rectum of each parabola is 3, then the equation of the common tangent to the two parabolas is :a)8(2x + y) + 3 = 0b)3(x + y) + 4 = 0c)4(x + y) + 3 = 0d)x + 2y + 3 = 0Correct answer is option 'C'. Can you explain this answer?.
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