JEE Exam  >  JEE Questions  >  One mole of an ideal monatomic gas is compres... Start Learning for Free
One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27°C. The work done on the gas will be: 
  • a)
    300 R ln 7
  • b)
    300 R ln 6
  • c)
    300 R ln 2
  • d)
    300 R
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
One mole of an ideal monatomic gas is compressed isothermally in a rig...


= 300R ln 2
View all questions of this test
Most Upvoted Answer
One mole of an ideal monatomic gas is compressed isothermally in a rig...
To solve this problem, we can use the ideal gas law:

PV = nRT

Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature

Since we have one mole of gas, we can rewrite the equation as:

PV = RT

For an isothermal process, the temperature remains constant. Therefore, we can write:

P1V1 = P2V2

Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume

We want to find the final volume V2 when the pressure is doubled (P2 = 2P1). We can substitute this into the equation:

P1V1 = 2P1V2

Simplifying the equation, we get:

V1 = 2V2

Therefore, the final volume will be half of the initial volume.

Now, we need to determine the initial volume V1. We know that the gas is at room temperature, which is 27 degrees Celsius or 300 Kelvin. We can assume that the gas behaves ideally, which means we can use the ideal gas law to find V1.

P1V1 = nRT

Since we have one mole of gas, we can simplify the equation to:

P1V1 = RT

V1 = (RT) / P1

Let's assume the pressure P1 is 1 atmosphere (atm), and the ideal gas constant R is 0.0821 L·atm/(mol·K). Substituting these values into the equation, we get:

V1 = (0.0821 L·atm/(mol·K) * 300 K) / 1 atm
V1 = 24.63 L

Therefore, the initial volume V1 is 24.63 liters.

Using the relationship V1 = 2V2, we can find the final volume V2:

V2 = V1 / 2
V2 = 24.63 L / 2
V2 = 12.32 L

Therefore, the final volume V2 when the gas is compressed isothermally to double its pressure is 12.32 liters.
Explore Courses for JEE exam
One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27°C. The work done on the gas will be:a)300 R ln 7b)300 R ln 6c)300 R ln 2d)300 RCorrect answer is option 'C'. Can you explain this answer?
Question Description
One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27°C. The work done on the gas will be:a)300 R ln 7b)300 R ln 6c)300 R ln 2d)300 RCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27°C. The work done on the gas will be:a)300 R ln 7b)300 R ln 6c)300 R ln 2d)300 RCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27°C. The work done on the gas will be:a)300 R ln 7b)300 R ln 6c)300 R ln 2d)300 RCorrect answer is option 'C'. Can you explain this answer?.
Solutions for One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27°C. The work done on the gas will be:a)300 R ln 7b)300 R ln 6c)300 R ln 2d)300 RCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27°C. The work done on the gas will be:a)300 R ln 7b)300 R ln 6c)300 R ln 2d)300 RCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27°C. The work done on the gas will be:a)300 R ln 7b)300 R ln 6c)300 R ln 2d)300 RCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27°C. The work done on the gas will be:a)300 R ln 7b)300 R ln 6c)300 R ln 2d)300 RCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27°C. The work done on the gas will be:a)300 R ln 7b)300 R ln 6c)300 R ln 2d)300 RCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27°C. The work done on the gas will be:a)300 R ln 7b)300 R ln 6c)300 R ln 2d)300 RCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev