JEE Exam > JEE Questions > On interchanging the resistances, the balane ...
Start Learning for Free
On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?
- a)990 Ω
- b)505 Ω
- c)550 Ω
- d)910 Ω
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
On interchanging the resistances, the balane point of a meter bridge s...
R1 + R2 =1000
R2 =1000−R1
On balancing condition,
R1 (100−l)=(1000−R1)l (1)
On interchanging resistance
On balancing condition
(1000−R1)(110−l)=R1(l−10)
R1(l−10)=(1000−R1)(110−l) (2)
On dividing (1) by (2)
(100−l) / l−10 = I / (110−l)
=> l = 55
On putting l=55 in equation (1), we get,
R1(100−55)=(1000−R1)55
On solving we will get R1 =550Ω
This question is part of UPSC exam. View all JEE courses
Most Upvoted Answer
On interchanging the resistances, the balane point of a meter bridge s...
Given Information:
- Balance point shifted to the left by 10cm after interchanging resistances
- Resistance of series combination is 1 kΩ
Let's solve the problem step by step:
1. Initial Situation:
- Let the initial resistances in the left and right slots be \(R_L\) and \(R_R\) respectively.
- The balance point is initially at a distance \(x\) from the left end.
2. After Interchanging Resistances:
- The resistances in the left and right slots become \(R_R\) and \(R_L\) respectively.
- The balance point shifts to a new position at a distance \(x+10\) from the left end.
3. Balance Point Condition:
- According to the principle of Wheatstone bridge, the product of resistances in the slots on each side of the balance point is equal.
- Therefore, \(R_L \times x = R_R \times (100-x)\)
4. Given Conditions:
- The resistance of series combination is 1 kΩ (1000 Ω).
- So, we have \(R_L + R_R = 1000 \Omega\)
5. Solving the Equations:
- From the balance point condition, we have \(R_L \times x = R_R \times (100-x)\)
- Substituting \(R_R = 1000 - R_L\) in the above equation, we get \(R_L \times x = (1000-R_L) \times (100-x)\)
- Solving this equation, we find \(R_L = 550 \Omega\)
6. Final Answer:
- The resistance in the left slot before interchanging the resistances was 550 Ω.
Therefore, the correct answer is option (c) 550 Ω.
- Balance point shifted to the left by 10cm after interchanging resistances
- Resistance of series combination is 1 kΩ
Let's solve the problem step by step:
1. Initial Situation:
- Let the initial resistances in the left and right slots be \(R_L\) and \(R_R\) respectively.
- The balance point is initially at a distance \(x\) from the left end.
2. After Interchanging Resistances:
- The resistances in the left and right slots become \(R_R\) and \(R_L\) respectively.
- The balance point shifts to a new position at a distance \(x+10\) from the left end.
3. Balance Point Condition:
- According to the principle of Wheatstone bridge, the product of resistances in the slots on each side of the balance point is equal.
- Therefore, \(R_L \times x = R_R \times (100-x)\)
4. Given Conditions:
- The resistance of series combination is 1 kΩ (1000 Ω).
- So, we have \(R_L + R_R = 1000 \Omega\)
5. Solving the Equations:
- From the balance point condition, we have \(R_L \times x = R_R \times (100-x)\)
- Substituting \(R_R = 1000 - R_L\) in the above equation, we get \(R_L \times x = (1000-R_L) \times (100-x)\)
- Solving this equation, we find \(R_L = 550 \Omega\)
6. Final Answer:
- The resistance in the left slot before interchanging the resistances was 550 Ω.
Therefore, the correct answer is option (c) 550 Ω.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer?
Question Description
On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer?.
On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer?.
Solutions for On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup