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On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?
- a)990 Ω
- b)505 Ω
- c)550 Ω
- d)910 Ω
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
On interchanging the resistances, the balane point of a meter bridge s...
R1 + R2 =1000
R2 =1000−R1
On balancing condition,
R1 (100−l)=(1000−R1)l (1)
On interchanging resistance
On balancing condition
(1000−R1)(110−l)=R1(l−10)
R1(l−10)=(1000−R1)(110−l) (2)
On dividing (1) by (2)
(100−l) / l−10 = I / (110−l)
=> l = 55
On putting l=55 in equation (1), we get,
R1(100−55)=(1000−R1)55
On solving we will get R1 =550Ω
This question is part of UPSC exam. View all JEE courses
Most Upvoted Answer
On interchanging the resistances, the balane point of a meter bridge s...
Given Information:
- Balance point shifted to the left by 10cm after interchanging resistances
- Resistance of series combination is 1 kΩ
Let's solve the problem step by step:
1. Initial Situation:
- Let the initial resistances in the left and right slots be \(R_L\) and \(R_R\) respectively.
- The balance point is initially at a distance \(x\) from the left end.
2. After Interchanging Resistances:
- The resistances in the left and right slots become \(R_R\) and \(R_L\) respectively.
- The balance point shifts to a new position at a distance \(x+10\) from the left end.
3. Balance Point Condition:
- According to the principle of Wheatstone bridge, the product of resistances in the slots on each side of the balance point is equal.
- Therefore, \(R_L \times x = R_R \times (100-x)\)
4. Given Conditions:
- The resistance of series combination is 1 kΩ (1000 Ω).
- So, we have \(R_L + R_R = 1000 \Omega\)
5. Solving the Equations:
- From the balance point condition, we have \(R_L \times x = R_R \times (100-x)\)
- Substituting \(R_R = 1000 - R_L\) in the above equation, we get \(R_L \times x = (1000-R_L) \times (100-x)\)
- Solving this equation, we find \(R_L = 550 \Omega\)
6. Final Answer:
- The resistance in the left slot before interchanging the resistances was 550 Ω.
Therefore, the correct answer is option (c) 550 Ω.
- Balance point shifted to the left by 10cm after interchanging resistances
- Resistance of series combination is 1 kΩ
Let's solve the problem step by step:
1. Initial Situation:
- Let the initial resistances in the left and right slots be \(R_L\) and \(R_R\) respectively.
- The balance point is initially at a distance \(x\) from the left end.
2. After Interchanging Resistances:
- The resistances in the left and right slots become \(R_R\) and \(R_L\) respectively.
- The balance point shifts to a new position at a distance \(x+10\) from the left end.
3. Balance Point Condition:
- According to the principle of Wheatstone bridge, the product of resistances in the slots on each side of the balance point is equal.
- Therefore, \(R_L \times x = R_R \times (100-x)\)
4. Given Conditions:
- The resistance of series combination is 1 kΩ (1000 Ω).
- So, we have \(R_L + R_R = 1000 \Omega\)
5. Solving the Equations:
- From the balance point condition, we have \(R_L \times x = R_R \times (100-x)\)
- Substituting \(R_R = 1000 - R_L\) in the above equation, we get \(R_L \times x = (1000-R_L) \times (100-x)\)
- Solving this equation, we find \(R_L = 550 \Omega\)
6. Final Answer:
- The resistance in the left slot before interchanging the resistances was 550 Ω.
Therefore, the correct answer is option (c) 550 Ω.
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On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer?
Question Description
On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer?.
On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer?.
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On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of On interchanging the resistances, the balane point of a meter bridge shifts to the left by 10cm. The resistance of their series combinations is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances?a)990 Ωb)505 Ωc)550 Ωd)910 ΩCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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