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If the motion of a particle is described by x = 5 cos(8πt), y = 5 sin(8πt) and z = 5t, then the trajectory of the particle is
  • a)
    Circular
  • b)
    Elliptical
  • c)
    Helical
  • d)
    Spiral
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If the motion of a particle is described by x = 5 cos(8πt), y = 5 s...
T), where x is the position of the particle and t is time in seconds, then the motion of the particle is a simple harmonic motion with an amplitude of 5 units and a period of π/4 seconds.

The position of the particle at any time t can be found by substituting the value of t in the given equation:

x = 5 cos(8t)

For example, if t = 0, then

x = 5 cos(0) = 5

This means that the particle is at its maximum position, which is 5 units to the right of its equilibrium position.

Similarly, if t = π/16, then

x = 5 cos(8π/16) = 5 cos(π/2) = 0

This means that the particle is at its equilibrium position, which is the center point of its motion.

If t = π/8, then

x = 5 cos(8π/8) = -5

This means that the particle is at its maximum position to the left of its equilibrium position.

Therefore, the motion of the particle is a simple harmonic motion with an amplitude of 5 units and a period of π/4 seconds.
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If the motion of a particle is described by x = 5 cos(8πt), y = 5 s...
C cuz xsq+ysq=5sq



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If the motion of a particle is described by x = 5 cos(8πt), y = 5 sin(8πt) and z = 5t, then the trajectory of the particle isa)Circularb)Ellipticalc)Helicald)SpiralCorrect answer is option 'C'. Can you explain this answer?
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