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Two balls A and B having masses 1 kg and 2 kg, moving with speeds 21 m/s and 4 m/s respectively in opposite direction, collide head on. After collision A moves with a speed of 1 m/s in the same direction, then the coefficient of restitution is
- a)0.1
- b)0.2
- c)0.4
- d)None
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Two balls A and B having masses 1 kg and 2 kg, moving with speeds 21 m...
Assuming external forces = 0
1 x 21 – 2 x 4 = 1 x 1 + 2 x v
So, v = 6m/s along the direction of A
Now, e = ((6) - (1))/((21) - (-4))
Hence e = 0.2
1 x 21 – 2 x 4 = 1 x 1 + 2 x v
So, v = 6m/s along the direction of A
Now, e = ((6) - (1))/((21) - (-4))
Hence e = 0.2
Most Upvoted Answer
Two balls A and B having masses 1 kg and 2 kg, moving with speeds 21 m...
Given:
Mass of ball A (m1) = 1 kg
Mass of ball B (m2) = 2 kg
Initial velocity of ball A (u1) = 21 m/s
Initial velocity of ball B (u2) = -4 m/s (opposite direction)
Let's find the velocity of the balls after the collision using the principle of conservation of linear momentum.
1. Conservation of linear momentum:
According to the principle of conservation of linear momentum, the total momentum before the collision is equal to the total momentum after the collision.
Initial momentum = Final momentum
m1 * u1 + m2 * u2 = m1 * v1 + m2 * v2
where,
v1 = final velocity of ball A after the collision
v2 = final velocity of ball B after the collision
2. Applying the given information:
Substituting the given values into the equation, we get:
1 * 21 + 2 * (-4) = 1 * v1 + 2 * v2
21 - 8 = v1 + 2v2
13 = v1 + 2v2 ...........(1)
3. Using the coefficient of restitution:
The coefficient of restitution (e) is defined as the ratio of relative velocity of separation to the relative velocity of approach between two bodies after their collision.
e = (v2 - v1) / (u1 - u2)
Given that A moves with a speed of 1 m/s in the same direction after the collision, we can rewrite the equation as:
e = (v2 - v1) / (u1 - u2) = (1 - 0) / (21 - (-4)) = 1 / 25 = 0.04
4. Comparing with the options:
The given options are:
a) 0.1
b) 0.2
c) 0.4
d) None
From the calculation, we found that the coefficient of restitution (e) is 0.04. None of the given options match with the calculated value.
Therefore, the correct answer is d) None.
Mass of ball A (m1) = 1 kg
Mass of ball B (m2) = 2 kg
Initial velocity of ball A (u1) = 21 m/s
Initial velocity of ball B (u2) = -4 m/s (opposite direction)
Let's find the velocity of the balls after the collision using the principle of conservation of linear momentum.
1. Conservation of linear momentum:
According to the principle of conservation of linear momentum, the total momentum before the collision is equal to the total momentum after the collision.
Initial momentum = Final momentum
m1 * u1 + m2 * u2 = m1 * v1 + m2 * v2
where,
v1 = final velocity of ball A after the collision
v2 = final velocity of ball B after the collision
2. Applying the given information:
Substituting the given values into the equation, we get:
1 * 21 + 2 * (-4) = 1 * v1 + 2 * v2
21 - 8 = v1 + 2v2
13 = v1 + 2v2 ...........(1)
3. Using the coefficient of restitution:
The coefficient of restitution (e) is defined as the ratio of relative velocity of separation to the relative velocity of approach between two bodies after their collision.
e = (v2 - v1) / (u1 - u2)
Given that A moves with a speed of 1 m/s in the same direction after the collision, we can rewrite the equation as:
e = (v2 - v1) / (u1 - u2) = (1 - 0) / (21 - (-4)) = 1 / 25 = 0.04
4. Comparing with the options:
The given options are:
a) 0.1
b) 0.2
c) 0.4
d) None
From the calculation, we found that the coefficient of restitution (e) is 0.04. None of the given options match with the calculated value.
Therefore, the correct answer is d) None.
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Two balls A and B having masses 1 kg and 2 kg, moving with speeds 21 m/s and 4 m/s respectively in opposite direction, collide head on. After collision A moves with a speed of 1 m/s in the same direction, then the coefficient of restitution isa)0.1b)0.2c)0.4d)NoneCorrect answer is option 'B'. Can you explain this answer?
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Two balls A and B having masses 1 kg and 2 kg, moving with speeds 21 m/s and 4 m/s respectively in opposite direction, collide head on. After collision A moves with a speed of 1 m/s in the same direction, then the coefficient of restitution isa)0.1b)0.2c)0.4d)NoneCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two balls A and B having masses 1 kg and 2 kg, moving with speeds 21 m/s and 4 m/s respectively in opposite direction, collide head on. After collision A moves with a speed of 1 m/s in the same direction, then the coefficient of restitution isa)0.1b)0.2c)0.4d)NoneCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two balls A and B having masses 1 kg and 2 kg, moving with speeds 21 m/s and 4 m/s respectively in opposite direction, collide head on. After collision A moves with a speed of 1 m/s in the same direction, then the coefficient of restitution isa)0.1b)0.2c)0.4d)NoneCorrect answer is option 'B'. Can you explain this answer?.
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