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In a Young's double slit experiment, slit s are separated by 0.5 mm, and the screen is placed 150 cm away. A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide is
- a)9.75 mm
- b)15.6 mm
- c)1.56 mm
- d)7.8 mm
Correct answer is option 'D'. Can you explain this answer?
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In a Young's double slit experiment, slit s are separated by 0.5 m...
Calculation:
- Given data: slit separation (d) = 0.5 mm = 0.5 x 10^-3 m, screen distance (D) = 150 cm = 1.5 m, wavelengths (λ1) = 650 nm = 650 x 10^-9 m, (λ2) = 520 nm = 520 x 10^-9 m
Formula:
- The condition for the bright fringes to coincide for two wavelengths is given by: d sinθ = mλ1 = nλ2, where m and n are integers
Calculations:
- For the central maximum, sinθ = 1, so the central maximum for both wavelengths coincide
- For the first order maximum (m = 1), we have: d sinθ = λ1, sinθ = λ1 / d = 650 x 10^-9 / 0.5 x 10^-3 = 1.3 x 10^-3
- For the second order maximum (n = 2), we have: d sinθ = 2λ2, sinθ = 2λ2 / d = 2 x 520 x 10^-9 / 0.5 x 10^-3 = 2.08 x 10^-3
Final calculations:
- The least distance from the common central maximum to the point where the bright fringes coincide for both wavelengths is given by: Dtanθ = Dsinθ = D(1.3 x 10^-3 - 2.08 x 10^-3) = 1.5(1.3 - 2.08) x 10^-3 = -0.78 x 10^-3 m = 7.8 mm
Therefore, the correct answer is option 'D' (7.8 mm).
- Given data: slit separation (d) = 0.5 mm = 0.5 x 10^-3 m, screen distance (D) = 150 cm = 1.5 m, wavelengths (λ1) = 650 nm = 650 x 10^-9 m, (λ2) = 520 nm = 520 x 10^-9 m
Formula:
- The condition for the bright fringes to coincide for two wavelengths is given by: d sinθ = mλ1 = nλ2, where m and n are integers
Calculations:
- For the central maximum, sinθ = 1, so the central maximum for both wavelengths coincide
- For the first order maximum (m = 1), we have: d sinθ = λ1, sinθ = λ1 / d = 650 x 10^-9 / 0.5 x 10^-3 = 1.3 x 10^-3
- For the second order maximum (n = 2), we have: d sinθ = 2λ2, sinθ = 2λ2 / d = 2 x 520 x 10^-9 / 0.5 x 10^-3 = 2.08 x 10^-3
Final calculations:
- The least distance from the common central maximum to the point where the bright fringes coincide for both wavelengths is given by: Dtanθ = Dsinθ = D(1.3 x 10^-3 - 2.08 x 10^-3) = 1.5(1.3 - 2.08) x 10^-3 = -0.78 x 10^-3 m = 7.8 mm
Therefore, the correct answer is option 'D' (7.8 mm).
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In a Young's double slit experiment, slit s are separated by 0.5 mm, and the screen is placed 150 cm away. A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide isa)9.75 mmb)15.6 mmc)1.56 mmd)7.8 mmCorrect answer is option 'D'. Can you explain this answer?
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In a Young's double slit experiment, slit s are separated by 0.5 mm, and the screen is placed 150 cm away. A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide isa)9.75 mmb)15.6 mmc)1.56 mmd)7.8 mmCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a Young's double slit experiment, slit s are separated by 0.5 mm, and the screen is placed 150 cm away. A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide isa)9.75 mmb)15.6 mmc)1.56 mmd)7.8 mmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a Young's double slit experiment, slit s are separated by 0.5 mm, and the screen is placed 150 cm away. A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide isa)9.75 mmb)15.6 mmc)1.56 mmd)7.8 mmCorrect answer is option 'D'. Can you explain this answer?.
In a Young's double slit experiment, slit s are separated by 0.5 mm, and the screen is placed 150 cm away. A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide isa)9.75 mmb)15.6 mmc)1.56 mmd)7.8 mmCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a Young's double slit experiment, slit s are separated by 0.5 mm, and the screen is placed 150 cm away. A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide isa)9.75 mmb)15.6 mmc)1.56 mmd)7.8 mmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a Young's double slit experiment, slit s are separated by 0.5 mm, and the screen is placed 150 cm away. A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide isa)9.75 mmb)15.6 mmc)1.56 mmd)7.8 mmCorrect answer is option 'D'. Can you explain this answer?.
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