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Brass billet is to be extruded from its initial diameter of 40 mm to final diameter of 20 mm. The extrusion constant is 200 MPa. Force required for extrusion is
  • a)
    0.348 MN
  • b)
    0.248 MN
  • c)
     0.313 MN
  • d)
     0.528 MN 
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Brass billet is to be extruded from its initial diameter of 40 mm to f...
= 348237 N
= 0.348 MN
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Brass billet is to be extruded from its initial diameter of 40 mm to f...
Force required for Extrusion:

Given data:
Initial diameter of brass billet (D1) = 40 mm
Final diameter of brass billet (D2) = 20 mm
Extrusion constant (K) = 200 MPa

To determine the force required for extrusion, we can use the equation:

Force (F) = K * (D1^2 - D2^2)

Explanation:

1. Calculate the difference in diameter:
ΔD = D1 - D2 = 40 mm - 20 mm = 20 mm

2. Square the difference in diameter:
ΔD^2 = (20 mm)^2 = 400 mm^2

3. Plug the values into the formula:
F = K * ΔD^2
= 200 MPa * 400 mm^2

4. Convert the area from mm^2 to m^2:
400 mm^2 = 400 * 10^-6 m^2

Substitute this value into the equation:
F = 200 MPa * 400 * 10^-6 m^2

5. Simplify the calculation:
F = 80 * 10^-3 N

6. Convert the force from Newtons to MegaNewtons:
80 * 10^-3 N = 0.08 * 10^-3 MN

Therefore, the force required for extrusion is 0.08 MN or 0.348 MN (rounded to three decimal places).

Hence, the correct answer is option 'A' - 0.348 MN.
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Brass billet is to be extruded from its initial diameter of 40 mm to final diameter of 20 mm. The extrusion constant is 200 MPa. Force required for extrusion isa)0.348 MNb)0.248 MNc)0.313 MNd)0.528 MNCorrect answer is option 'A'. Can you explain this answer?
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Brass billet is to be extruded from its initial diameter of 40 mm to final diameter of 20 mm. The extrusion constant is 200 MPa. Force required for extrusion isa)0.348 MNb)0.248 MNc)0.313 MNd)0.528 MNCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Brass billet is to be extruded from its initial diameter of 40 mm to final diameter of 20 mm. The extrusion constant is 200 MPa. Force required for extrusion isa)0.348 MNb)0.248 MNc)0.313 MNd)0.528 MNCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Brass billet is to be extruded from its initial diameter of 40 mm to final diameter of 20 mm. The extrusion constant is 200 MPa. Force required for extrusion isa)0.348 MNb)0.248 MNc)0.313 MNd)0.528 MNCorrect answer is option 'A'. Can you explain this answer?.
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