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During a non-flow isothermal reversible expansion, 1 kmol of at 350 k expands from 0.06 to 0.15 .Use Vander waals equation to determine
Work done during process
  • a)
    2.65 kJ/ kmol
  • b)
    2.65 MJ/k mol
  • c)
    1.32 kJ/k mol
  • d)
    1.32 MJ/k mol
Correct answer is option 'B'. Can you explain this answer?
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During a non-flow isothermal reversible expansion, 1 kmol of at 350 k...

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During a non-flow isothermal reversible expansion, 1 kmol of at 350 k expands from 0.06 to 0.15 .Use Vander waals equation to determine Work done during process a)2.65 kJ/ kmolb)2.65 MJ/k molc)1.32 kJ/k mold)1.32 MJ/k molCorrect answer is option 'B'. Can you explain this answer?
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During a non-flow isothermal reversible expansion, 1 kmol of at 350 k expands from 0.06 to 0.15 .Use Vander waals equation to determine Work done during process a)2.65 kJ/ kmolb)2.65 MJ/k molc)1.32 kJ/k mold)1.32 MJ/k molCorrect answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about During a non-flow isothermal reversible expansion, 1 kmol of at 350 k expands from 0.06 to 0.15 .Use Vander waals equation to determine Work done during process a)2.65 kJ/ kmolb)2.65 MJ/k molc)1.32 kJ/k mold)1.32 MJ/k molCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for During a non-flow isothermal reversible expansion, 1 kmol of at 350 k expands from 0.06 to 0.15 .Use Vander waals equation to determine Work done during process a)2.65 kJ/ kmolb)2.65 MJ/k molc)1.32 kJ/k mold)1.32 MJ/k molCorrect answer is option 'B'. Can you explain this answer?.
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