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A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.?
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A wire 50 cm long is stretched by 60N . The mass per unit length of th...
The fundamental frequency of the first node in a standing wave in a wire is given by,
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A wire 50 cm long is stretched by 60N . The mass per unit length of th...
Calculating Frequency of Fundamental Mode in a Vibrating String
Calculating Tension in the Wire:
- Given length of the wire, L = 50 cm = 0.5 m
- Tension in the wire, T = 60 N
Calculating Mass of the Wire:
- Mass per unit length, μ = 1×10^-5 kg/m
- Mass of the wire, m = μL = 1×10^-5 kg/m * 0.5 m = 5×10^-6 kg
Calculating Speed of Wave in the Wire:
- Speed of wave, v = √(T/μ) = √(60 N / 5×10^-6 kg) = √(1.2×10^7 m/s) = 3454.1 m/s
Calculating Frequency of Fundamental Mode:
- Fundamental frequency, f = v / 2L = 3454.1 m/s / (2*0.5 m) = 3454.1 Hz
Therefore, the frequency of the fundamental mode emitted by the vibrating string is 3454.1 Hz.
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A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.?
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A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.?.
A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.?.
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