Class 11 Exam > Class 11 Questions > A wire 50 cm long is stretched by 60N . The m...
Start Learning for Free
A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.?
Most Upvoted Answer
A wire 50 cm long is stretched by 60N . The mass per unit length of th...
The fundamental frequency of the first node in a standing wave in a wire is given by,
Community Answer
A wire 50 cm long is stretched by 60N . The mass per unit length of th...
Calculating Frequency of Fundamental Mode in a Vibrating String
Calculating Tension in the Wire:
- Given length of the wire, L = 50 cm = 0.5 m
- Tension in the wire, T = 60 N
Calculating Mass of the Wire:
- Mass per unit length, μ = 1×10^-5 kg/m
- Mass of the wire, m = μL = 1×10^-5 kg/m * 0.5 m = 5×10^-6 kg
Calculating Speed of Wave in the Wire:
- Speed of wave, v = √(T/μ) = √(60 N / 5×10^-6 kg) = √(1.2×10^7 m/s) = 3454.1 m/s
Calculating Frequency of Fundamental Mode:
- Fundamental frequency, f = v / 2L = 3454.1 m/s / (2*0.5 m) = 3454.1 Hz
Therefore, the frequency of the fundamental mode emitted by the vibrating string is 3454.1 Hz.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.?
Question Description
A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.?.
A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.?.
Solutions for A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? defined & explained in the simplest way possible. Besides giving the explanation of
A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.?, a detailed solution for A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? has been provided alongside types of A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? theory, EduRev gives you an
ample number of questions to practice A wire 50 cm long is stretched by 60N . The mass per unit length of the wire is 1×10^-5 kg/m . Calculate the frequency of fundamental mode emitted by vibrating string.? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup