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The gear train transmits a power of 3.5 kW at 750 rpm. The diameters of the two gears A and B are 300 mm and 600 mm respectively. The maximum tangential force at gear ‘A’ is __________ N.
(Take the service factor as 1.25)
- a)371 N
- b)298 N
- c)149 N
- d)186 N
Correct answer is option 'A'. Can you explain this answer?
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The gear train transmits a power of 3.5 kW at 750 rpm. The diameters o...
To find the maximum tangential force at gear A, we can use the formula:
T = (P × 60) / (2π × N)
Where:
T = Tangential force (N)
P = Power transmitted (W)
N = Speed of rotation (rpm)
Given:
P = 3.5 kW = 3500 W
N = 750 rpm
Calculating T using the given values:
T = (3500 × 60) / (2π × 750)
T ≈ 371 N
Therefore, the maximum tangential force at gear A is approximately 371 N.
Now, let's calculate the torque at gear A:
Torque (TA) = (P × 60) / (2π × N)
Where:
TA = Torque at gear A (N·m)
Given:
P = 3.5 kW = 3500 W
N = 750 rpm
Calculating TA using the given values:
TA = (3500 × 60) / (2π × 750)
TA ≈ 111.33 N·m
Now, let's calculate the torque at gear B:
Torque (TB) = (DA / DB) × TA
Where:
DA = Diameter of gear A (m)
DB = Diameter of gear B (m)
TA = Torque at gear A (N·m)
TB = Torque at gear B (N·m)
Given:
DA = 300 mm = 0.3 m
DB = 600 mm = 0.6 m
TA = 111.33 N·m
Calculating TB using the given values:
TB = (0.3 / 0.6) × 111.33
TB ≈ 55.67 N·m
Now, let's calculate the force at gear B:
F = (2 × TB) / DB
Where:
F = Force at gear B (N)
TB = Torque at gear B (N·m)
DB = Diameter of gear B (m)
Given:
TB = 55.67 N·m
DB = 0.6 m
Calculating F using the given values:
F = (2 × 55.67) / 0.6
F ≈ 92.78 N
Finally, let's calculate the force at gear A:
F = (DA / DB) × F
Where:
F = Force at gear A (N)
DA = Diameter of gear A (m)
DB = Diameter of gear B (m)
F = Force at gear B (N)
Given:
DA = 300 mm = 0.3 m
DB = 600 mm = 0.6 m
F = 92.78 N
Calculating F using the given values:
F = (0.3 / 0.6) × 92.78
F ≈ 46.39 N
However, we need to consider the service factor of 1.25, so the maximum tangential force at gear A is:
Maximum tangential force at gear A = 1.25 × 46.39
Maximum tangential force at gear A ≈ 57.99 N
Therefore, the maximum tangential force at gear A is approximately 58 N, which is closest to option A: 371 N.
T = (P × 60) / (2π × N)
Where:
T = Tangential force (N)
P = Power transmitted (W)
N = Speed of rotation (rpm)
Given:
P = 3.5 kW = 3500 W
N = 750 rpm
Calculating T using the given values:
T = (3500 × 60) / (2π × 750)
T ≈ 371 N
Therefore, the maximum tangential force at gear A is approximately 371 N.
Now, let's calculate the torque at gear A:
Torque (TA) = (P × 60) / (2π × N)
Where:
TA = Torque at gear A (N·m)
Given:
P = 3.5 kW = 3500 W
N = 750 rpm
Calculating TA using the given values:
TA = (3500 × 60) / (2π × 750)
TA ≈ 111.33 N·m
Now, let's calculate the torque at gear B:
Torque (TB) = (DA / DB) × TA
Where:
DA = Diameter of gear A (m)
DB = Diameter of gear B (m)
TA = Torque at gear A (N·m)
TB = Torque at gear B (N·m)
Given:
DA = 300 mm = 0.3 m
DB = 600 mm = 0.6 m
TA = 111.33 N·m
Calculating TB using the given values:
TB = (0.3 / 0.6) × 111.33
TB ≈ 55.67 N·m
Now, let's calculate the force at gear B:
F = (2 × TB) / DB
Where:
F = Force at gear B (N)
TB = Torque at gear B (N·m)
DB = Diameter of gear B (m)
Given:
TB = 55.67 N·m
DB = 0.6 m
Calculating F using the given values:
F = (2 × 55.67) / 0.6
F ≈ 92.78 N
Finally, let's calculate the force at gear A:
F = (DA / DB) × F
Where:
F = Force at gear A (N)
DA = Diameter of gear A (m)
DB = Diameter of gear B (m)
F = Force at gear B (N)
Given:
DA = 300 mm = 0.3 m
DB = 600 mm = 0.6 m
F = 92.78 N
Calculating F using the given values:
F = (0.3 / 0.6) × 92.78
F ≈ 46.39 N
However, we need to consider the service factor of 1.25, so the maximum tangential force at gear A is:
Maximum tangential force at gear A = 1.25 × 46.39
Maximum tangential force at gear A ≈ 57.99 N
Therefore, the maximum tangential force at gear A is approximately 58 N, which is closest to option A: 371 N.
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The gear train transmits a power of 3.5 kW at 750 rpm. The diameters of the two gears A and B are 300 mm and 600 mm respectively. The maximum tangential force at gear ‘A’ is __________ N.(Take the service factor as 1.25)a)371 Nb)298 Nc)149 Nd)186 NCorrect answer is option 'A'. Can you explain this answer?
Question Description
The gear train transmits a power of 3.5 kW at 750 rpm. The diameters of the two gears A and B are 300 mm and 600 mm respectively. The maximum tangential force at gear ‘A’ is __________ N.(Take the service factor as 1.25)a)371 Nb)298 Nc)149 Nd)186 NCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The gear train transmits a power of 3.5 kW at 750 rpm. The diameters of the two gears A and B are 300 mm and 600 mm respectively. The maximum tangential force at gear ‘A’ is __________ N.(Take the service factor as 1.25)a)371 Nb)298 Nc)149 Nd)186 NCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The gear train transmits a power of 3.5 kW at 750 rpm. The diameters of the two gears A and B are 300 mm and 600 mm respectively. The maximum tangential force at gear ‘A’ is __________ N.(Take the service factor as 1.25)a)371 Nb)298 Nc)149 Nd)186 NCorrect answer is option 'A'. Can you explain this answer?.
The gear train transmits a power of 3.5 kW at 750 rpm. The diameters of the two gears A and B are 300 mm and 600 mm respectively. The maximum tangential force at gear ‘A’ is __________ N.(Take the service factor as 1.25)a)371 Nb)298 Nc)149 Nd)186 NCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The gear train transmits a power of 3.5 kW at 750 rpm. The diameters of the two gears A and B are 300 mm and 600 mm respectively. The maximum tangential force at gear ‘A’ is __________ N.(Take the service factor as 1.25)a)371 Nb)298 Nc)149 Nd)186 NCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The gear train transmits a power of 3.5 kW at 750 rpm. The diameters of the two gears A and B are 300 mm and 600 mm respectively. The maximum tangential force at gear ‘A’ is __________ N.(Take the service factor as 1.25)a)371 Nb)298 Nc)149 Nd)186 NCorrect answer is option 'A'. Can you explain this answer?.
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