R(vector) = A(vector)+B(vector) | R |² =[ |A|² + |B|² + 2AB (cos x) ]|R|=3 |A|=|B|=√33² = (√3)² + (√3)² +2 * √3 * √3 (cos x)9 = 3+3 + 2*3* (cos x)9 = 6 + 6(cos x)9-6 = 6 (cos x)3=6 (cos x)3/6 = 1/2 =0.5 = (cos x) hencex= 60° = π/3here x is angle between vector

Given information:
- Vector A = √3
- Vector B = √3
- Vector C = 3

To find:
- The angle between vectors A and B

Explanation:
To find the angle between two vectors, we can use the dot product formula:

A · B = |A| |B| cosθ

where A · B is the dot product of vectors A and B, |A| and |B| are the magnitudes of vectors A and B respectively, and θ is the angle between them.

Let's calculate the dot product of vectors A and B:

A · B = (√3)(√3) = 3

We are given that A · B = C, which means the dot product of vectors A and B is equal to the magnitude of vector C.

Since the dot product is equal to the product of magnitudes and the cosine of the angle, we can write:

C = |A| |B| cosθ

Substituting the given values:

3 = (√3)(√3) cosθ

Simplifying:

3 = 3 cosθ

Dividing both sides by 3:

1 = cosθ

Calculating the angle:
Now we need to find the angle whose cosine is 1. The cosine of an angle is equal to 1 when the angle is 0 degrees. Similarly, the cosine is also 1 when the angle is 360 degrees or any multiple of 360 degrees.

Therefore, the angle between vectors A and B is 0 degrees or 360 degrees.

Final Answer:
The angle between vectors A and B is 0 degrees or 360 degrees.