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The nuclear spin quantum number (I) of a nucleus is 3/2. When placed in an external magnetic field, the number of possible spin energy states it can occupy is ______.
Correct answer is between '4,4'. Can you explain this answer?
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The nuclear spin quantum number (I) of a nucleus is 3/2.When placed in...
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Explanation:
When a nucleus is placed in an external magnetic field, it experiences a magnetic moment due to the nuclear spin. The magnetic moment is proportional to the nuclear spin quantum number (I) and the strength of the external magnetic field (B).
The energy of the nuclear spin in the magnetic field can be described by the Zeeman effect. The Zeeman effect splits the energy levels of the nuclear spin into discrete energy states. The number of possible spin energy states depends on the value of nuclear spin quantum number (I).
The formula for the number of energy states is given by:
2I + 1
Where I is the nuclear spin quantum number.
Therefore, for a nucleus with I = 3/2, the number of possible spin energy states it can occupy is:
2(3/2) + 1 = 4
Hence, the correct answer is 4.
Explanation:
When a nucleus is placed in an external magnetic field, it experiences a magnetic moment due to the nuclear spin. The magnetic moment is proportional to the nuclear spin quantum number (I) and the strength of the external magnetic field (B).
The energy of the nuclear spin in the magnetic field can be described by the Zeeman effect. The Zeeman effect splits the energy levels of the nuclear spin into discrete energy states. The number of possible spin energy states depends on the value of nuclear spin quantum number (I).
The formula for the number of energy states is given by:
2I + 1
Where I is the nuclear spin quantum number.
Therefore, for a nucleus with I = 3/2, the number of possible spin energy states it can occupy is:
2(3/2) + 1 = 4
Hence, the correct answer is 4.
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