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If the sum of the squares of the distances of a point from the three coordinate axes be 36, then its distance from the origin is
  • a)
    6
  • b)
    3√2
  • c)
    2√3
  • d)
    6√2
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If the sum of the squares of the distances of apoint from the three co...
Let (x,y,z) be the point.
Given sum of the squares of distance from point to the axes is 36. 
⇒(x2+y2)+(y2+z2)+(z2+x2)=36
⇒2(x2+y2+z2)=36⇒x2+y2+z2=18
So the distance of the point from the origin is =3(2)1/2
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Community Answer
If the sum of the squares of the distances of apoint from the three co...
Let the coordinates of the point be $(x,y,z)$. Then we have \begin{align*}
x^2+y^2+z^2 &= 36 \\
x^2+y^2 &= 36-z^2 \\
y^2+z^2 &= 36-x^2 \\
z^2+x^2 &= 36-y^2 \\
\end{align*} Adding all of these equations, we get $2(x^2+y^2+z^2) = 108$, which simplifies to $x^2+y^2+z^2 = 54$. Substituting this back into the original equation, we get $54 = 36$-$z^2$, so $z^2 = 18$. Therefore, the distance from the origin is $\sqrt{x^2+y^2+z^2} = \sqrt{54} = \boxed{3\sqrt{6}}$.
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If the sum of the squares of the distances of apoint from the three coordinate axes be 36, then itsdistance from the origin isa)6b)3√2c)2√3d)6√2Correct answer is option 'B'. Can you explain this answer?
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