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A series AC circuit containing an inductor (20 mH), a capacitor (120 μF) and a resistor (60Ω) is driven by an AC source of 24 V/50 Hz. The energy dissipated in the circuit in 60 s is :
  • a)
    2.26 × 103 J
  • b)
    3.39 × 103 J
  • c)
    5.65 × 102 J
  • d)
    5.17 × 102 J
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A series AC circuit containing an inductor (20 mH), a capacitor (120 &...
R = 60Ω f = 50Hz, ω = 2πf = 100 π




Q = P.t = 8.64 × 60 = 5.18 × 102
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Most Upvoted Answer
A series AC circuit containing an inductor (20 mH), a capacitor (120 &...
ΜF), and a resistor (50 Ω) is supplied with a voltage of 120 V at a frequency of 50 Hz. What is the impedance of the circuit?

We can use the formula for calculating the impedance of a series AC circuit:

Z = √(R^2 + (XL - XC)^2)

where R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance.

First, we need to calculate the values of XL and XC:

XL = 2πfL = 2π × 50 × 0.02 = 6.28 Ω
XC = 1/(2πfC) = 1/(2π × 50 × 0.00012) = 132.2 Ω

Now we can plug in the values to the formula:

Z = √(50^2 + (6.28 - 132.2)^2) = √(2500 + 17424) = √19924 = 141.1 Ω

Therefore, the impedance of the circuit is 141.1 Ω.
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A series AC circuit containing an inductor (20 mH), a capacitor (120 μF) and a resistor (60Ω) is driven by an AC source of 24 V/50 Hz. The energy dissipated in the circuit in 60 s is :a)2.26 × 103 Jb)3.39 × 103 Jc)5.65 × 102 Jd)5.17 × 102 JCorrect answer is option 'D'. Can you explain this answer?
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A series AC circuit containing an inductor (20 mH), a capacitor (120 μF) and a resistor (60Ω) is driven by an AC source of 24 V/50 Hz. The energy dissipated in the circuit in 60 s is :a)2.26 × 103 Jb)3.39 × 103 Jc)5.65 × 102 Jd)5.17 × 102 JCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A series AC circuit containing an inductor (20 mH), a capacitor (120 μF) and a resistor (60Ω) is driven by an AC source of 24 V/50 Hz. The energy dissipated in the circuit in 60 s is :a)2.26 × 103 Jb)3.39 × 103 Jc)5.65 × 102 Jd)5.17 × 102 JCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A series AC circuit containing an inductor (20 mH), a capacitor (120 μF) and a resistor (60Ω) is driven by an AC source of 24 V/50 Hz. The energy dissipated in the circuit in 60 s is :a)2.26 × 103 Jb)3.39 × 103 Jc)5.65 × 102 Jd)5.17 × 102 JCorrect answer is option 'D'. Can you explain this answer?.
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