The charge on a metallic sphere of radius 9 centimetre is 4 into 10 to...
GIVEN:
CHARGE ON THE METALLIC SPHERE Q = 4 *10-6 C
RADIUS OF THE SPHERE r = 9 cm = 0.09 m
potential energy of charge on the conductor is given by the relation
E=KQ/r
=9 INTO 10 TO THE POWER OF 9 INTO 4 INTO 10 TO THE POWER OF MINUS 6 / 0.09
=4 into 10 to the power 5 joule
POTENTIAL ENERGY OF CHARGE ON THE CONDUCTOR IS 4 INTO 10 TO THE POWER OF 5 JOULE
The charge on a metallic sphere of radius 9 centimetre is 4 into 10 to...
To calculate the potential energy of a charge on a conductor, we need to consider the formula:
Potential Energy (PE) = Q * V
Where:
- PE is the potential energy
- Q is the charge on the conductor
- V is the potential difference across the conductor
In this case, the charge on the metallic sphere is given as 4 * 10^-6 coulomb. However, the potential difference across the conductor is not provided. Hence, we need to find the potential difference using the formula:
V = k * (Q / r)
Where:
- V is the potential difference
- k is the electrostatic constant (9 * 10^9 Nm²/C²)
- Q is the charge on the conductor
- r is the radius of the conductor
Using the given values, we can substitute them into the formula to find the potential difference:
V = (9 * 10^9 Nm²/C²) * (4 * 10^-6 C) / (9 cm)
- Convert the radius from centimeters to meters: 9 cm = 0.09 m
- Calculate the potential difference:
V = (9 * 10^9 Nm²/C²) * (4 * 10^-6 C) / (0.09 m)
= (9 * 10^9 * 4 * 10^-6) / 0.09
= (36 * 10^3) / 0.09
= 400 * 10^3 V
= 4 * 10^5 V
Now that we have the potential difference, we can calculate the potential energy using the formula mentioned earlier:
PE = Q * V
= (4 * 10^-6 C) * (4 * 10^5 V)
= 16 * 10^-6 * 10^5 C * V
= 16 * 10^-1 C * V
= 16 * 10^4 CV
= 1.6 * 10^4 CV
Hence, the potential energy of the charge on the conductor is 1.6 * 10^4 CV.