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Three pipes A, B and C are connected to a tank such that A can fill the empty tank in 4 hours, B and C can empty the filled tank individually in 8 hours and 10 hours respectively. When the tank is empty, two or more pipes are opened simultaneously such that the tank started filling with water. Find the maximum amount of time for which Pipe A would be open such that the tank was empty exactly at the end of 20 hours.
  • a)
    20 hours
  • b)
    18 hours
  • c)
     hours
  • d)
    hours
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Three pipes A, B and C are connected to a tank such that A can fill th...
Let the capacity of the tank be 40 units.
Therefore, in one hour, A fills 10 units, while B and C empties 5 and 4 units of the tank individually.
For A to be open for maximum time, both B and C also should be open for maximum time. If B and C are open for 20 hours, they can drain (5 + 4) x 20 = 180 litres of water.
So, the maximum time for which pipe A would be open = 180/10 =18 hours.
Hence, option 2.
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Most Upvoted Answer
Three pipes A, B and C are connected to a tank such that A can fill th...
Let the capacity of the tank be 40 units.
Therefore, in one hour, A fills 10 units, while B and C empties 5 and 4 units of the tank individually.
For A to be open for maximum time, both B and C also should be open for maximum time. If B and C are open for 20 hours, they can drain (5 + 4) x 20 = 180 litres of water.
So, the maximum time for which pipe A would be open = 180/10 =18 hours.
Hence, option 2.
Free Test
Community Answer
Three pipes A, B and C are connected to a tank such that A can fill th...
Let time required be t
since two or more pipes are opened but asking for maximum amount so we go for three
so in one hour tank will be filled=( 1/4-1/8-1/10) parts 
so in x hours it will be filled =(1/4-1/8-1/10) x parts
since whole process take place in 20 hours so time remaing for emptying it =20-t
accordingly tank filled in ' t ' hours = tank will be emptied in 20-t hours
=(1/4-1/8-1/10) x t =(1/8+1/10) x (20-t)
or t/40=9/2-9t/40
or t/4=9/2
or t= 18 hours
therefore option b is correct

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Three pipes A, B and C are connected to a tank such that A can fill the empty tank in 4 hours, B and C can empty the filled tank individually in 8 hours and 10 hours respectively. When the tank is empty, two or more pipes are opened simultaneously such that the tank started filling with water. Find the maximum amount of time for which Pipe A would be open such that the tank was empty exactly at the end of 20 hours.a)20 hoursb)18 hoursc)hoursd) hourse)None of theseCorrect answer is option 'B'. Can you explain this answer?
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