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From a solid sphere of mass M and radius R, a spherical portion of radius R/2 is removed, as shown in the figure. Taking gravitational potential V = 0 at r = ∞, the potential at the centre of the cavity thus formed is (G = gravitational constant)
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
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From a solid sphere of mass M and radius R, a spherical portion of rad...

 
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From a solid sphere of mass M and radius R, a spherical portion of rad...
In solid sphere surface is equipotential that's why potential at all points inside is same so it will be equal to surface=-gm/r
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From a solid sphere of mass M and radius R, a spherical portion of rad...

 
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From a solid sphere of mass M and radius R, a spherical portion of radius R/2 is removed, as shown in the figure. Taking gravitational potential V = 0 at r = ∞, the potential at the centre of the cavity thus formed is(G = gravitational constant)a)b)c)d)Correct answer is option 'B'. Can you explain this answer?
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From a solid sphere of mass M and radius R, a spherical portion of radius R/2 is removed, as shown in the figure. Taking gravitational potential V = 0 at r = ∞, the potential at the centre of the cavity thus formed is(G = gravitational constant)a)b)c)d)Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about From a solid sphere of mass M and radius R, a spherical portion of radius R/2 is removed, as shown in the figure. Taking gravitational potential V = 0 at r = ∞, the potential at the centre of the cavity thus formed is(G = gravitational constant)a)b)c)d)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for From a solid sphere of mass M and radius R, a spherical portion of radius R/2 is removed, as shown in the figure. Taking gravitational potential V = 0 at r = ∞, the potential at the centre of the cavity thus formed is(G = gravitational constant)a)b)c)d)Correct answer is option 'B'. Can you explain this answer?.
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