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A uniformly charged solid sphere of radius R has potential V0 (measured with respect to ¥) on its surface. For this sphere the equipotential surfaces with potentials  have radius R1, R2, R3 and R4 respectively. Then
  • a)
    R1 = 0 and R2 > (R4 – R3
  • b)
    R1 = 0 and R2 < (R4 – R3)
  • c)
    2R < R
  • d)
    both B and C
Correct answer is option 'D'. Can you explain this answer?
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A uniformly charged solid sphere of radius R has potential V0 (measured with respect to ¥) on its surface. For this sphere the equipotential surfaceswith potentialshave radiusR1, R2, R3 and R4 respectively. Thena)R1 = 0 and R2 > (R4 – R3)b)R1 = 0 and R2 < (R4 – R3)c)2R < R4d)both B and CCorrect answer is option 'D'. Can you explain this answer?
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A uniformly charged solid sphere of radius R has potential V0 (measured with respect to ¥) on its surface. For this sphere the equipotential surfaceswith potentialshave radiusR1, R2, R3 and R4 respectively. Thena)R1 = 0 and R2 > (R4 – R3)b)R1 = 0 and R2 < (R4 – R3)c)2R < R4d)both B and CCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A uniformly charged solid sphere of radius R has potential V0 (measured with respect to ¥) on its surface. For this sphere the equipotential surfaceswith potentialshave radiusR1, R2, R3 and R4 respectively. Thena)R1 = 0 and R2 > (R4 – R3)b)R1 = 0 and R2 < (R4 – R3)c)2R < R4d)both B and CCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniformly charged solid sphere of radius R has potential V0 (measured with respect to ¥) on its surface. For this sphere the equipotential surfaceswith potentialshave radiusR1, R2, R3 and R4 respectively. Thena)R1 = 0 and R2 > (R4 – R3)b)R1 = 0 and R2 < (R4 – R3)c)2R < R4d)both B and CCorrect answer is option 'D'. Can you explain this answer?.
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