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A cylindrical packed bed of height 1 m is filled with equal sized spherical particles. The particles
are nonporous and have a density of 1500 kg/m3. The void fraction of the bed is 0.45. The bed is
fluidized using air (density 1kg/m3). If the acceleration due to gravity is 9.8m/s2, the pressure drop
(in pa) across the bed at incipient fluidization (up to one decimal place ) is _________.
are nonporous and have a density of 1500 kg/m3. The void fraction of the bed is 0.45. The bed is
fluidized using air (density 1kg/m3). If the acceleration due to gravity is 9.8m/s2, the pressure drop
(in pa) across the bed at incipient fluidization (up to one decimal place ) is _________.
Correct answer is '8079.61'. Can you explain this answer?
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Given information:
- Height of the cylindrical packed bed = 1 m
- Density of the particles = 1500 kg/m3
- Void fraction of the bed = 0.45
- Density of air = 1 kg/m3
- Acceleration due to gravity = 9.8 m/s2
Calculating the pressure drop:
The pressure drop across the bed at incipient fluidization can be calculated using the Ergun equation, which relates the pressure drop to the velocity of the fluid through the bed.
Ergun equation:
The Ergun equation is given by:
ΔP/L = 150 (1 - ε)^2 (ρu/ε^3) + 1.75 ρu^2 (1 - ε)/ε^3
Where:
- ΔP/L is the pressure drop per unit length of the bed
- ε is the void fraction of the bed
- ρu is the density of the fluid-solid mixture
Calculating the density of the fluid-solid mixture:
The density of the fluid-solid mixture can be calculated using the equation:
ρu = ε ρp + (1 - ε) ρf
Where:
- ρp is the density of the particles
- ρf is the density of the fluid
Substituting the given values into the equation:
ρu = 0.45 * 1500 + (1 - 0.45) * 1 = 1500 * 0.45 + 0.55 = 675 + 0.55 = 675.55 kg/m3
Calculating the pressure drop:
Substituting the values of ε and ρu into the Ergun equation:
ΔP/L = 150 (1 - 0.45)^2 (675.55/0.45^3) + 1.75 * 675.55^2 (1 - 0.45)/0.45^3
Simplifying the equation:
ΔP/L = 150 * 0.55^2 * 675.55/0.45^3 + 1.75 * 675.55^2 * 0.55/0.45^3
Calculating the pressure drop:
ΔP/L = 8079.61 Pa
Answer:
The pressure drop across the bed at incipient fluidization is 8079.61 Pa.
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A cylindrical packed bed of height 1 m is filled with equal sized spherical particles. The particlesare nonporous and have a density of 1500 kg/m3. The void fraction of the bed is 0.45. The bed isfluidized using air (density 1kg/m3). If the acceleration due to gravity is 9.8m/s2, the pressure drop(in pa) across the bed at incipient fluidization (up to one decimal place ) is _________.Correct answer is '8079.61'. Can you explain this answer?
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A cylindrical packed bed of height 1 m is filled with equal sized spherical particles. The particlesare nonporous and have a density of 1500 kg/m3. The void fraction of the bed is 0.45. The bed isfluidized using air (density 1kg/m3). If the acceleration due to gravity is 9.8m/s2, the pressure drop(in pa) across the bed at incipient fluidization (up to one decimal place ) is _________.Correct answer is '8079.61'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A cylindrical packed bed of height 1 m is filled with equal sized spherical particles. The particlesare nonporous and have a density of 1500 kg/m3. The void fraction of the bed is 0.45. The bed isfluidized using air (density 1kg/m3). If the acceleration due to gravity is 9.8m/s2, the pressure drop(in pa) across the bed at incipient fluidization (up to one decimal place ) is _________.Correct answer is '8079.61'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylindrical packed bed of height 1 m is filled with equal sized spherical particles. The particlesare nonporous and have a density of 1500 kg/m3. The void fraction of the bed is 0.45. The bed isfluidized using air (density 1kg/m3). If the acceleration due to gravity is 9.8m/s2, the pressure drop(in pa) across the bed at incipient fluidization (up to one decimal place ) is _________.Correct answer is '8079.61'. Can you explain this answer?.
A cylindrical packed bed of height 1 m is filled with equal sized spherical particles. The particlesare nonporous and have a density of 1500 kg/m3. The void fraction of the bed is 0.45. The bed isfluidized using air (density 1kg/m3). If the acceleration due to gravity is 9.8m/s2, the pressure drop(in pa) across the bed at incipient fluidization (up to one decimal place ) is _________.Correct answer is '8079.61'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A cylindrical packed bed of height 1 m is filled with equal sized spherical particles. The particlesare nonporous and have a density of 1500 kg/m3. The void fraction of the bed is 0.45. The bed isfluidized using air (density 1kg/m3). If the acceleration due to gravity is 9.8m/s2, the pressure drop(in pa) across the bed at incipient fluidization (up to one decimal place ) is _________.Correct answer is '8079.61'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylindrical packed bed of height 1 m is filled with equal sized spherical particles. The particlesare nonporous and have a density of 1500 kg/m3. The void fraction of the bed is 0.45. The bed isfluidized using air (density 1kg/m3). If the acceleration due to gravity is 9.8m/s2, the pressure drop(in pa) across the bed at incipient fluidization (up to one decimal place ) is _________.Correct answer is '8079.61'. Can you explain this answer?.
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