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A spherical naphthalene ball of 2mm diameter is subliming very slowly in stagnant air at 25OC.
The change in the size of the ball during the sublimation can be neglected. The diffusivity of
naphthalene in air at 25o C is 1.1×10-6 m2/s.
The value of mass transfer coefficient is B × 10-3 m/s, where B (up to one decimal place) is
The change in the size of the ball during the sublimation can be neglected. The diffusivity of
naphthalene in air at 25o C is 1.1×10-6 m2/s.
The value of mass transfer coefficient is B × 10-3 m/s, where B (up to one decimal place) is
Imp : you should answer only the numeric value
Correct answer is '1.1'. Can you explain this answer?
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A spherical naphthalene ball of 2mm diameter is subliming very slowly ...
For spherical ball
Dimensionless sherwood number = 2
Dimensionless sherwood number = 2
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A spherical naphthalene ball of 2mm diameter is subliming very slowly ...
To find the rate of sublimation of the naphthalene ball, we can use Fick's law of diffusion:
Rate of sublimation = -D * A * (dC/dx)
Where:
- D is the diffusivity of naphthalene in air at 25°C, which is given as 1.1
- A is the surface area of the naphthalene ball
- dC/dx is the concentration gradient of naphthalene in air
Since the change in the size of the ball during sublimation can be neglected, we can assume that the naphthalene ball maintains its original surface area throughout the process. Therefore, we can calculate the surface area of the ball using the formula for the surface area of a sphere:
A = 4 * π * r^2
Where:
- r is the radius of the naphthalene ball, which is half of the diameter given as 2mm, so r = 1mm = 0.001m
A = 4 * π * (0.001)^2
A = 0.00001257 m^2
Now, we need to determine the concentration gradient of naphthalene in air. Since the air is stagnant, the concentration gradient can be assumed to be constant. Let's assume the concentration of naphthalene at the surface of the ball is Cs (in kg/m^3) and the concentration of naphthalene in the bulk air is C∞ (in kg/m^3).
The concentration gradient, dC/dx, is then given by:
dC/dx = (Cs - C∞) / x
Where:
- Cs is the concentration at the surface of the ball
- C∞ is the concentration in the bulk air
- x is the distance from the surface of the ball, which is constant throughout the ball and can be taken as the radius of the ball, 0.001m
Since the naphthalene ball is subliming very slowly, we can assume that the concentration at the surface of the ball is approximately equal to the concentration in the bulk air, Cs ≈ C∞. Therefore, the concentration gradient simplifies to:
dC/dx = (Cs - C∞) / x
dC/dx = 0 / x
dC/dx = 0
Since the concentration gradient is zero, the rate of sublimation is also zero. This means that the naphthalene ball is not subliming in stagnant air at 25°C.
Rate of sublimation = -D * A * (dC/dx)
Where:
- D is the diffusivity of naphthalene in air at 25°C, which is given as 1.1
- A is the surface area of the naphthalene ball
- dC/dx is the concentration gradient of naphthalene in air
Since the change in the size of the ball during sublimation can be neglected, we can assume that the naphthalene ball maintains its original surface area throughout the process. Therefore, we can calculate the surface area of the ball using the formula for the surface area of a sphere:
A = 4 * π * r^2
Where:
- r is the radius of the naphthalene ball, which is half of the diameter given as 2mm, so r = 1mm = 0.001m
A = 4 * π * (0.001)^2
A = 0.00001257 m^2
Now, we need to determine the concentration gradient of naphthalene in air. Since the air is stagnant, the concentration gradient can be assumed to be constant. Let's assume the concentration of naphthalene at the surface of the ball is Cs (in kg/m^3) and the concentration of naphthalene in the bulk air is C∞ (in kg/m^3).
The concentration gradient, dC/dx, is then given by:
dC/dx = (Cs - C∞) / x
Where:
- Cs is the concentration at the surface of the ball
- C∞ is the concentration in the bulk air
- x is the distance from the surface of the ball, which is constant throughout the ball and can be taken as the radius of the ball, 0.001m
Since the naphthalene ball is subliming very slowly, we can assume that the concentration at the surface of the ball is approximately equal to the concentration in the bulk air, Cs ≈ C∞. Therefore, the concentration gradient simplifies to:
dC/dx = (Cs - C∞) / x
dC/dx = 0 / x
dC/dx = 0
Since the concentration gradient is zero, the rate of sublimation is also zero. This means that the naphthalene ball is not subliming in stagnant air at 25°C.
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A spherical naphthalene ball of 2mm diameter is subliming very slowly in stagnant air at 25OC.The change in the size of the ball during the sublimation can be neglected. The diffusivity ofnaphthalene in air at 25o C is 1.1×10-6 m2/s.The value of mass transfer coefficient is B × 10-3 m/s, where B (up to one decimal place) isImp : you should answer only the numeric valueCorrect answer is '1.1'. Can you explain this answer?
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A spherical naphthalene ball of 2mm diameter is subliming very slowly in stagnant air at 25OC.The change in the size of the ball during the sublimation can be neglected. The diffusivity ofnaphthalene in air at 25o C is 1.1×10-6 m2/s.The value of mass transfer coefficient is B × 10-3 m/s, where B (up to one decimal place) isImp : you should answer only the numeric valueCorrect answer is '1.1'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A spherical naphthalene ball of 2mm diameter is subliming very slowly in stagnant air at 25OC.The change in the size of the ball during the sublimation can be neglected. The diffusivity ofnaphthalene in air at 25o C is 1.1×10-6 m2/s.The value of mass transfer coefficient is B × 10-3 m/s, where B (up to one decimal place) isImp : you should answer only the numeric valueCorrect answer is '1.1'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spherical naphthalene ball of 2mm diameter is subliming very slowly in stagnant air at 25OC.The change in the size of the ball during the sublimation can be neglected. The diffusivity ofnaphthalene in air at 25o C is 1.1×10-6 m2/s.The value of mass transfer coefficient is B × 10-3 m/s, where B (up to one decimal place) isImp : you should answer only the numeric valueCorrect answer is '1.1'. Can you explain this answer?.
A spherical naphthalene ball of 2mm diameter is subliming very slowly in stagnant air at 25OC.The change in the size of the ball during the sublimation can be neglected. The diffusivity ofnaphthalene in air at 25o C is 1.1×10-6 m2/s.The value of mass transfer coefficient is B × 10-3 m/s, where B (up to one decimal place) isImp : you should answer only the numeric valueCorrect answer is '1.1'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A spherical naphthalene ball of 2mm diameter is subliming very slowly in stagnant air at 25OC.The change in the size of the ball during the sublimation can be neglected. The diffusivity ofnaphthalene in air at 25o C is 1.1×10-6 m2/s.The value of mass transfer coefficient is B × 10-3 m/s, where B (up to one decimal place) isImp : you should answer only the numeric valueCorrect answer is '1.1'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spherical naphthalene ball of 2mm diameter is subliming very slowly in stagnant air at 25OC.The change in the size of the ball during the sublimation can be neglected. The diffusivity ofnaphthalene in air at 25o C is 1.1×10-6 m2/s.The value of mass transfer coefficient is B × 10-3 m/s, where B (up to one decimal place) isImp : you should answer only the numeric valueCorrect answer is '1.1'. Can you explain this answer?.
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