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A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n = 1to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon ofwavelength λe. Let the change in momentum of atom due to the absorption and the emission are Δpaand Δpe, respectively. IfWhich of the option(s) is/are correct?[Use hc = 1242 eV nm; 1 nm = 10–9 m, h and c are Plancks constant and speed of light, respectively]a)λe = 418 nmb)The ratio of kinetic energy of the electron in the state n = m to the state n = 1 is 1/4c)m = 2d)Δpa/Δpe= 1/2Correct answer is option 'B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n = 1to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon ofwavelength λe. Let the change in momentum of atom due to the absorption and the emission are Δpaand Δpe, respectively. IfWhich of the option(s) is/are correct?[Use hc = 1242 eV nm; 1 nm = 10–9 m, h and c are Plancks constant and speed of light, respectively]a)λe = 418 nmb)The ratio of kinetic energy of the electron in the state n = m to the state n = 1 is 1/4c)m = 2d)Δpa/Δpe= 1/2Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n = 1to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon ofwavelength λe. Let the change in momentum of atom due to the absorption and the emission are Δpaand Δpe, respectively. IfWhich of the option(s) is/are correct?[Use hc = 1242 eV nm; 1 nm = 10–9 m, h and c are Plancks constant and speed of light, respectively]a)λe = 418 nmb)The ratio of kinetic energy of the electron in the state n = m to the state n = 1 is 1/4c)m = 2d)Δpa/Δpe= 1/2Correct answer is option 'B,C'. Can you explain this answer?.

Solutions for A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n = 1to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon ofwavelength λe. Let the change in momentum of atom due to the absorption and the emission are Δpaand Δpe, respectively. IfWhich of the option(s) is/are correct?[Use hc = 1242 eV nm; 1 nm = 10–9 m, h and c are Plancks constant and speed of light, respectively]a)λe = 418 nmb)The ratio of kinetic energy of the electron in the state n = m to the state n = 1 is 1/4c)m = 2d)Δpa/Δpe= 1/2Correct answer is option 'B,C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n = 1to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon ofwavelength λe. Let the change in momentum of atom due to the absorption and the emission are Δpaand Δpe, respectively. IfWhich of the option(s) is/are correct?[Use hc = 1242 eV nm; 1 nm = 10–9 m, h and c are Plancks constant and speed of light, respectively]a)λe = 418 nmb)The ratio of kinetic energy of the electron in the state n = m to the state n = 1 is 1/4c)m = 2d)Δpa/Δpe= 1/2Correct answer is option 'B,C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n = 1to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon ofwavelength λe. Let the change in momentum of atom due to the absorption and the emission are Δpaand Δpe, respectively. IfWhich of the option(s) is/are correct?[Use hc = 1242 eV nm; 1 nm = 10–9 m, h and c are Plancks constant and speed of light, respectively]a)λe = 418 nmb)The ratio of kinetic energy of the electron in the state n = m to the state n = 1 is 1/4c)m = 2d)Δpa/Δpe= 1/2Correct answer is option 'B,C'. Can you explain this answer?, a detailed solution for A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n = 1to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon ofwavelength λe. Let the change in momentum of atom due to the absorption and the emission are Δpaand Δpe, respectively. IfWhich of the option(s) is/are correct?[Use hc = 1242 eV nm; 1 nm = 10–9 m, h and c are Plancks constant and speed of light, respectively]a)λe = 418 nmb)The ratio of kinetic energy of the electron in the state n = m to the state n = 1 is 1/4c)m = 2d)Δpa/Δpe= 1/2Correct answer is option 'B,C'. Can you explain this answer? has been provided alongside types of A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n = 1to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon ofwavelength λe. Let the change in momentum of atom due to the absorption and the emission are Δpaand Δpe, respectively. IfWhich of the option(s) is/are correct?[Use hc = 1242 eV nm; 1 nm = 10–9 m, h and c are Plancks constant and speed of light, respectively]a)λe = 418 nmb)The ratio of kinetic energy of the electron in the state n = m to the state n = 1 is 1/4c)m = 2d)Δpa/Δpe= 1/2Correct answer is option 'B,C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A free hydrogen atom after absorbing a photon of wavelength λa gets excited from the state n = 1to the state n = 4. Immediately after that the electron jumps to n = m state by emitting a photon ofwavelength λe. Let the change in momentum of atom due to the absorption and the emission are Δpaand Δpe, respectively. IfWhich of the option(s) is/are correct?[Use hc = 1242 eV nm; 1 nm = 10–9 m, h and c are Plancks constant and speed of light, respectively]a)λe = 418 nmb)The ratio of kinetic energy of the electron in the state n = m to the state n = 1 is 1/4c)m = 2d)Δpa/Δpe= 1/2Correct answer is option 'B,C'. Can you explain this answer? tests, examples and also practice JEE tests.