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The external and internal diameters of a hollow cylinder are determined with the vernier calipers the result s are recorded as 4.23 0.01 and 3.89 0.01 CM determine the thickness of the cylinder wall with the limits of error.?
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The external and internal diameters of a hollow cylinder are determine...
Solution:

To determine the thickness of the cylinder wall, we need to subtract the internal diameter from the external diameter.

Given data:
External diameter = 4.23 cm ± 0.01 cm
Internal diameter = 3.89 cm ± 0.01 cm

Step 1: Determining the average diameter
To find the average diameter, we add the external and internal diameters and divide the sum by 2.

Average diameter = (external diameter + internal diameter) / 2
Average diameter = (4.23 cm + 3.89 cm) / 2
Average diameter = 8.12 cm / 2
Average diameter = 4.06 cm

Step 2: Determining the thickness
To find the thickness, we subtract the internal diameter from the external diameter.

Thickness = External diameter - Internal diameter
Thickness = 4.23 cm - 3.89 cm
Thickness = 0.34 cm

Step 3: Determining the limits of error
To determine the limits of error, we need to consider the maximum and minimum values for both the external and internal diameters.

Maximum external diameter = 4.23 cm + 0.01 cm = 4.24 cm
Minimum external diameter = 4.23 cm - 0.01 cm = 4.22 cm

Maximum internal diameter = 3.89 cm + 0.01 cm = 3.90 cm
Minimum internal diameter = 3.89 cm - 0.01 cm = 3.88 cm

Maximum thickness = Maximum external diameter - Minimum internal diameter
Maximum thickness = 4.24 cm - 3.88 cm
Maximum thickness = 0.36 cm

Minimum thickness = Minimum external diameter - Maximum internal diameter
Minimum thickness = 4.22 cm - 3.90 cm
Minimum thickness = 0.32 cm

Therefore, the thickness of the cylinder wall is 0.34 cm with a maximum limit of error of 0.36 cm and a minimum limit of error of 0.32 cm.
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The external and internal diameters of a hollow cylinder are determine...
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The external and internal diameters of a hollow cylinder are determined with the vernier calipers the result s are recorded as 4.23 0.01 and 3.89 0.01 CM determine the thickness of the cylinder wall with the limits of error.?
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