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The external and internal diameters of a hollow cylinder are determined with the vernier calipers the result s are recorded as 4.23 0.01 and 3.89 0.01 CM determine the thickness of the cylinder wall with the limits of error.?
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The external and internal diameters of a hollow cylinder are determine...
Solution:
To determine the thickness of the cylinder wall, we need to subtract the internal diameter from the external diameter.
Given data:
External diameter = 4.23 cm ± 0.01 cm
Internal diameter = 3.89 cm ± 0.01 cm
Step 1: Determining the average diameter
To find the average diameter, we add the external and internal diameters and divide the sum by 2.
Average diameter = (external diameter + internal diameter) / 2
Average diameter = (4.23 cm + 3.89 cm) / 2
Average diameter = 8.12 cm / 2
Average diameter = 4.06 cm
Step 2: Determining the thickness
To find the thickness, we subtract the internal diameter from the external diameter.
Thickness = External diameter - Internal diameter
Thickness = 4.23 cm - 3.89 cm
Thickness = 0.34 cm
Step 3: Determining the limits of error
To determine the limits of error, we need to consider the maximum and minimum values for both the external and internal diameters.
Maximum external diameter = 4.23 cm + 0.01 cm = 4.24 cm
Minimum external diameter = 4.23 cm - 0.01 cm = 4.22 cm
Maximum internal diameter = 3.89 cm + 0.01 cm = 3.90 cm
Minimum internal diameter = 3.89 cm - 0.01 cm = 3.88 cm
Maximum thickness = Maximum external diameter - Minimum internal diameter
Maximum thickness = 4.24 cm - 3.88 cm
Maximum thickness = 0.36 cm
Minimum thickness = Minimum external diameter - Maximum internal diameter
Minimum thickness = 4.22 cm - 3.90 cm
Minimum thickness = 0.32 cm
Therefore, the thickness of the cylinder wall is 0.34 cm with a maximum limit of error of 0.36 cm and a minimum limit of error of 0.32 cm.
To determine the thickness of the cylinder wall, we need to subtract the internal diameter from the external diameter.
Given data:
External diameter = 4.23 cm ± 0.01 cm
Internal diameter = 3.89 cm ± 0.01 cm
Step 1: Determining the average diameter
To find the average diameter, we add the external and internal diameters and divide the sum by 2.
Average diameter = (external diameter + internal diameter) / 2
Average diameter = (4.23 cm + 3.89 cm) / 2
Average diameter = 8.12 cm / 2
Average diameter = 4.06 cm
Step 2: Determining the thickness
To find the thickness, we subtract the internal diameter from the external diameter.
Thickness = External diameter - Internal diameter
Thickness = 4.23 cm - 3.89 cm
Thickness = 0.34 cm
Step 3: Determining the limits of error
To determine the limits of error, we need to consider the maximum and minimum values for both the external and internal diameters.
Maximum external diameter = 4.23 cm + 0.01 cm = 4.24 cm
Minimum external diameter = 4.23 cm - 0.01 cm = 4.22 cm
Maximum internal diameter = 3.89 cm + 0.01 cm = 3.90 cm
Minimum internal diameter = 3.89 cm - 0.01 cm = 3.88 cm
Maximum thickness = Maximum external diameter - Minimum internal diameter
Maximum thickness = 4.24 cm - 3.88 cm
Maximum thickness = 0.36 cm
Minimum thickness = Minimum external diameter - Maximum internal diameter
Minimum thickness = 4.22 cm - 3.90 cm
Minimum thickness = 0.32 cm
Therefore, the thickness of the cylinder wall is 0.34 cm with a maximum limit of error of 0.36 cm and a minimum limit of error of 0.32 cm.
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The external and internal diameters of a hollow cylinder are determine...
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The external and internal diameters of a hollow cylinder are determined with the vernier calipers the result s are recorded as 4.23 0.01 and 3.89 0.01 CM determine the thickness of the cylinder wall with the limits of error.?
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The external and internal diameters of a hollow cylinder are determined with the vernier calipers the result s are recorded as 4.23 0.01 and 3.89 0.01 CM determine the thickness of the cylinder wall with the limits of error.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The external and internal diameters of a hollow cylinder are determined with the vernier calipers the result s are recorded as 4.23 0.01 and 3.89 0.01 CM determine the thickness of the cylinder wall with the limits of error.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The external and internal diameters of a hollow cylinder are determined with the vernier calipers the result s are recorded as 4.23 0.01 and 3.89 0.01 CM determine the thickness of the cylinder wall with the limits of error.?.
The external and internal diameters of a hollow cylinder are determined with the vernier calipers the result s are recorded as 4.23 0.01 and 3.89 0.01 CM determine the thickness of the cylinder wall with the limits of error.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The external and internal diameters of a hollow cylinder are determined with the vernier calipers the result s are recorded as 4.23 0.01 and 3.89 0.01 CM determine the thickness of the cylinder wall with the limits of error.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The external and internal diameters of a hollow cylinder are determined with the vernier calipers the result s are recorded as 4.23 0.01 and 3.89 0.01 CM determine the thickness of the cylinder wall with the limits of error.?.
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