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A di-atomic gas undergoes adiabatic expansion against the piston of a cylinder. As a result, the temperature of the gas drops from 1150 K to 400 K. The number of moles of the gas required to obtain 2300 J of work from the expansion is ________.(The gas constant R = 8.314 J mol–1K–1.)(Round off to 2 decimal places)Correct answer is between '0.14,0.16'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared
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the IIT JAM exam syllabus. Information about A di-atomic gas undergoes adiabatic expansion against the piston of a cylinder. As a result, the temperature of the gas drops from 1150 K to 400 K. The number of moles of the gas required to obtain 2300 J of work from the expansion is ________.(The gas constant R = 8.314 J mol–1K–1.)(Round off to 2 decimal places)Correct answer is between '0.14,0.16'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for A di-atomic gas undergoes adiabatic expansion against the piston of a cylinder. As a result, the temperature of the gas drops from 1150 K to 400 K. The number of moles of the gas required to obtain 2300 J of work from the expansion is ________.(The gas constant R = 8.314 J mol–1K–1.)(Round off to 2 decimal places)Correct answer is between '0.14,0.16'. Can you explain this answer?.
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Here you can find the meaning of A di-atomic gas undergoes adiabatic expansion against the piston of a cylinder. As a result, the temperature of the gas drops from 1150 K to 400 K. The number of moles of the gas required to obtain 2300 J of work from the expansion is ________.(The gas constant R = 8.314 J mol–1K–1.)(Round off to 2 decimal places)Correct answer is between '0.14,0.16'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A di-atomic gas undergoes adiabatic expansion against the piston of a cylinder. As a result, the temperature of the gas drops from 1150 K to 400 K. The number of moles of the gas required to obtain 2300 J of work from the expansion is ________.(The gas constant R = 8.314 J mol–1K–1.)(Round off to 2 decimal places)Correct answer is between '0.14,0.16'. Can you explain this answer?, a detailed solution for A di-atomic gas undergoes adiabatic expansion against the piston of a cylinder. As a result, the temperature of the gas drops from 1150 K to 400 K. The number of moles of the gas required to obtain 2300 J of work from the expansion is ________.(The gas constant R = 8.314 J mol–1K–1.)(Round off to 2 decimal places)Correct answer is between '0.14,0.16'. Can you explain this answer? has been provided alongside types of A di-atomic gas undergoes adiabatic expansion against the piston of a cylinder. As a result, the temperature of the gas drops from 1150 K to 400 K. The number of moles of the gas required to obtain 2300 J of work from the expansion is ________.(The gas constant R = 8.314 J mol–1K–1.)(Round off to 2 decimal places)Correct answer is between '0.14,0.16'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A di-atomic gas undergoes adiabatic expansion against the piston of a cylinder. As a result, the temperature of the gas drops from 1150 K to 400 K. The number of moles of the gas required to obtain 2300 J of work from the expansion is ________.(The gas constant R = 8.314 J mol–1K–1.)(Round off to 2 decimal places)Correct answer is between '0.14,0.16'. Can you explain this answer? tests, examples and also practice IIT JAM tests.