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A 10 cm long perfectly conducting wire PQ is moving, with a velocity 1cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x × 10–3A, where the value of x is_______.[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed.Given: e–1 = 0.37, where e is base of the natural logarithm]Correct answer is '0.63'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 10 cm long perfectly conducting wire PQ is moving, with a velocity 1cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x × 10–3A, where the value of x is_______.[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed.Given: e–1 = 0.37, where e is base of the natural logarithm]Correct answer is '0.63'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 10 cm long perfectly conducting wire PQ is moving, with a velocity 1cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x × 10–3A, where the value of x is_______.[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed.Given: e–1 = 0.37, where e is base of the natural logarithm]Correct answer is '0.63'. Can you explain this answer?.

Solutions for A 10 cm long perfectly conducting wire PQ is moving, with a velocity 1cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x × 10–3A, where the value of x is_______.[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed.Given: e–1 = 0.37, where e is base of the natural logarithm]Correct answer is '0.63'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of A 10 cm long perfectly conducting wire PQ is moving, with a velocity 1cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x × 10–3A, where the value of x is_______.[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed.Given: e–1 = 0.37, where e is base of the natural logarithm]Correct answer is '0.63'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A 10 cm long perfectly conducting wire PQ is moving, with a velocity 1cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x × 10–3A, where the value of x is_______.[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed.Given: e–1 = 0.37, where e is base of the natural logarithm]Correct answer is '0.63'. Can you explain this answer?, a detailed solution for A 10 cm long perfectly conducting wire PQ is moving, with a velocity 1cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x × 10–3A, where the value of x is_______.[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed.Given: e–1 = 0.37, where e is base of the natural logarithm]Correct answer is '0.63'. Can you explain this answer? has been provided alongside types of A 10 cm long perfectly conducting wire PQ is moving, with a velocity 1cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x × 10–3A, where the value of x is_______.[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed.Given: e–1 = 0.37, where e is base of the natural logarithm]Correct answer is '0.63'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A 10 cm long perfectly conducting wire PQ is moving, with a velocity 1cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1Ω as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x × 10–3A, where the value of x is_______.[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed.Given: e–1 = 0.37, where e is base of the natural logarithm]Correct answer is '0.63'. Can you explain this answer? tests, examples and also practice JEE tests.