**Answer:**

In the combustion of an alkane, such as methane (CH4), the reaction can be represented as:

**CnH2n+2 + (3n+1)/2 O2 → n CO2 + (n+1) H2O**

In this reaction, one mole of alkane reacts with (3n+1)/2 moles of oxygen to produce n moles of carbon dioxide and (n+1) moles of water.

Let's consider an alkane containing 'm' carbon atoms. Therefore, the alkane formula would be CmH2m+2.

**1. Determine the number of moles of alkane:**

Since we have one mole of alkane, the number of moles of alkane would be 1.

**2. Determine the number of moles of water formed:**

According to the balanced chemical equation, for every mole of alkane, (n+1) moles of water are formed.

Therefore, for one mole of alkane, (m+1) moles of water are formed.

**3. Determine the number of water molecules:**

To determine the number of water molecules, we need to consider Avogadro's number, which is approximately 6.022 x 10^23 molecules per mole.

Therefore, the number of water molecules formed would be (m+1) x Avogadro's number.

**4. Substitute the value of 'm' into the equation:**

Substituting the value of 'm' into the equation, we can determine the answer:

A) m

Therefore, the correct answer is A) m.