Complexes in which the oxidation number of a metal is zero is/area)Cr(C6H6)2b)[Mn(CN)6]4-c)[Ni(CO)4]d)All of theseCorrect answer is option 'C'. Can you explain this answer?

Question

Answer

In [Ni(CO)₄]
Let the oxidation state of Ni is x.
x + 4 x (0) = 0 (Carbonyl (CO) is a neutral ligand and have zero charge.)
x = 0
Hence, Ni have zero oxidation state.

Answer

In [Ni(CO)₄]
Let the oxidation state of Ni is x.
x + 4 x (0) = 0 (Carbonyl (CO) is a neutral ligand and have zero charge.)
x = 0
Hence, Ni have zero oxidation state.

Answer

C) [Ni(CO)4]
This answer is correct because if any metal is bonded with [CO] then it's oxidation state is zero.

Answer

Complexes in which the oxidation number of a metal is zero is [Ni(CO)4].

Explanation:

In a complex, the oxidation number of the metal is the charge that the metal would have if all the ligands were removed along with their accompanying electron pairs. In other words, it is the charge that the metal would have if it exists as an isolated ion.

Now let's analyze each option to determine the oxidation number of the metal:

a) Cr(C6H6)2:
The ligands in this complex are benzene molecules (C6H6). Benzene is a neutral molecule, so it does not contribute any charge to the complex. Since the overall charge of the complex is zero, the oxidation number of the metal (Cr) must also be zero. However, this complex is not the correct answer because Cr has an oxidation number of +3 in its most common form.

b) [Mn(CN)6]4-:
The ligand in this complex is cyanide (CN-), which carries a charge of -1. Since there are six cyanide ligands, the total charge contributed by the ligands is -6. The overall charge of the complex is -4, so the oxidation number of the metal (Mn) must be +2 to balance out the charges.

c) [Ni(CO)4]:
The ligand in this complex is carbon monoxide (CO), which is a neutral molecule. Therefore, it does not contribute any charge to the complex. Since the overall charge of the complex is zero, the oxidation number of the metal (Ni) must also be zero. This complex is the correct answer because the metal has an oxidation number of zero.

d) All of these:
This option is incorrect because the oxidation number of the metal in complexes a) and b) is not zero.

In conclusion, the complex in which the oxidation number of the metal is zero is [Ni(CO)4].

Answer

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