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In a photoelectric experiment a parallel beam of monochromatic light with power of 200 W is incident on a perfectly absorbing cathode of work function 6.25 eV. The frequency of light is just above the threshold frequency so that the photoelectrons are emitted with negligible kinetic energy. Assume that the photoelectron emission efficiency is 100%. A potential difference of 500 V is applied between the cathode and the anode. All the emitted electrons are incident normally on the anode and are absorbed. The anode experiences a force F= n ×10−4N due to the impact of the electrons. The value of n is __________. Mass of the electron me = 9 x 10-31kg and 1.0 eV = 1.6 ×10−19 j.
    Correct answer is '24'. Can you explain this answer?
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    In a photoelectric experiment a parallel beam of monochromatic light w...
    Let N be the number of photons emitted per second, then, P = Nhv 
    For negligible kinetic energy, the work function is equal to the energy of incident photon. Thus,


    The change in kinetic energy is calculated as,
    K = qV

    As the work efficiency is 100% , thus, the number of electrons is equal to the number of photons per second.
    The force experienced by the anode electrons is given as,

    n = 24
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    In a photoelectric experiment a parallel beam of monochromatic light with power of 200 W is incident on a perfectly absorbing cathode of work function 6.25 eV. The frequency of light is just above the threshold frequency so that the photoelectrons are emitted with negligible kinetic energy. Assume that the photoelectron emission efficiency is 100%. A potential difference of 500 V is applied between the cathode and the anode. All the emitted electrons are incident normally on the anode and are absorbed. The anode experiences a force F= n ×10−4N due to the impact of the electrons. The value of n is __________. Mass of the electron me= 9 x 10-31kg and1.0 eV = 1.6 ×10−19 j.Correct answer is '24'. Can you explain this answer?
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    In a photoelectric experiment a parallel beam of monochromatic light with power of 200 W is incident on a perfectly absorbing cathode of work function 6.25 eV. The frequency of light is just above the threshold frequency so that the photoelectrons are emitted with negligible kinetic energy. Assume that the photoelectron emission efficiency is 100%. A potential difference of 500 V is applied between the cathode and the anode. All the emitted electrons are incident normally on the anode and are absorbed. The anode experiences a force F= n ×10−4N due to the impact of the electrons. The value of n is __________. Mass of the electron me= 9 x 10-31kg and1.0 eV = 1.6 ×10−19 j.Correct answer is '24'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a photoelectric experiment a parallel beam of monochromatic light with power of 200 W is incident on a perfectly absorbing cathode of work function 6.25 eV. The frequency of light is just above the threshold frequency so that the photoelectrons are emitted with negligible kinetic energy. Assume that the photoelectron emission efficiency is 100%. A potential difference of 500 V is applied between the cathode and the anode. All the emitted electrons are incident normally on the anode and are absorbed. The anode experiences a force F= n ×10−4N due to the impact of the electrons. The value of n is __________. Mass of the electron me= 9 x 10-31kg and1.0 eV = 1.6 ×10−19 j.Correct answer is '24'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a photoelectric experiment a parallel beam of monochromatic light with power of 200 W is incident on a perfectly absorbing cathode of work function 6.25 eV. The frequency of light is just above the threshold frequency so that the photoelectrons are emitted with negligible kinetic energy. Assume that the photoelectron emission efficiency is 100%. A potential difference of 500 V is applied between the cathode and the anode. All the emitted electrons are incident normally on the anode and are absorbed. The anode experiences a force F= n ×10−4N due to the impact of the electrons. The value of n is __________. Mass of the electron me= 9 x 10-31kg and1.0 eV = 1.6 ×10−19 j.Correct answer is '24'. Can you explain this answer?.
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