Given following reaction,NaClO3 + Fe andrarr; O2 + FeO + NaClIn the above reaction 492 L of O2 is obtained at 1 atm andamp; 300 K temperature.Determine mass of NaClO3 required (in kg).(R = 0.082 L atm molandndash;1 Kandndash;1 )Correct answer is '2.13'. Can you explain this answer?

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Given following reaction,
NaClO₃ + Fe → O₂+ FeO + NaCl
In the above reaction 492 L of O₂ is obtained at 1 atm & 300 K temperature.
Determine mass of NaClO₃ required (in kg).
(R = 0.082 L atm mol^–1 K^–1 )

Correct answer is '2.13'. Can you explain this answer?

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Given following reaction,NaClO3 + Fe → O2 + FeO + NaClIn the abov...

mol of NaClO₃ = mol of O₂
mol of O₂=

= 20 mL
mass of NaClO₃= 20 × 106.5 = 2130 g

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Given following reaction,NaClO3 + Fe → O2 + FeO + NaClIn the above reaction 492 L of O2 is obtained at 1 atm & 300 K temperature.Determine mass of NaClO3 required (in kg).(R = 0.082 L atm mol–1 K–1 )Correct answer is '2.13'. Can you explain this answer?

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Given following reaction,NaClO3 + Fe → O2 + FeO + NaClIn the above reaction 492 L of O2 is obtained at 1 atm & 300 K temperature.Determine mass of NaClO3 required (in kg).(R = 0.082 L atm mol–1 K–1 )Correct answer is '2.13'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Given following reaction,NaClO3 + Fe → O2 + FeO + NaClIn the above reaction 492 L of O2 is obtained at 1 atm & 300 K temperature.Determine mass of NaClO3 required (in kg).(R = 0.082 L atm mol–1 K–1 )Correct answer is '2.13'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given following reaction,NaClO3 + Fe → O2 + FeO + NaClIn the above reaction 492 L of O2 is obtained at 1 atm & 300 K temperature.Determine mass of NaClO3 required (in kg).(R = 0.082 L atm mol–1 K–1 )Correct answer is '2.13'. Can you explain this answer?.

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