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The total number of DNA molecules present after 5 cycles of polymerase chain reaction (PCR) starting with 3 molecules of template DNA is ________.
Correct answer is '96 to 96'. Can you explain this answer?
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Most Upvoted Answer
The total number of DNA molecules present after 5 cycles of polymerase...
Explanation:
Polymerase chain reaction (PCR) is a laboratory technique used to amplify a specific DNA sequence. It is a cyclic process that involves three steps: denaturation, annealing, and extension.
Given:
- Template DNA molecules = 3
- Number of PCR cycles = 5
Calculation:
- In the first cycle, the 3 template DNA molecules will be denatured to single strands.
- In the second cycle, each of the single strands will anneal with a primer, and the DNA polymerase enzyme will extend the primer, creating two new DNA strands.
- In the third cycle, each of the four DNA strands will denature, creating 8 single strands.
- In the fourth cycle, each of the 8 single strands will anneal with a primer, and the DNA polymerase enzyme will extend the primer, creating 16 new DNA strands.
- In the fifth cycle, each of the 16 DNA strands will denature, creating 32 single strands.
- Each of these 32 single strands will anneal with a primer, and the DNA polymerase enzyme will extend the primer, creating 64 new DNA strands.
Therefore, the total number of DNA molecules present after 5 cycles of PCR starting with 3 molecules of template DNA is 96 to 96.
Final Answer: 96 to 96.
Polymerase chain reaction (PCR) is a laboratory technique used to amplify a specific DNA sequence. It is a cyclic process that involves three steps: denaturation, annealing, and extension.
Given:
- Template DNA molecules = 3
- Number of PCR cycles = 5
Calculation:
- In the first cycle, the 3 template DNA molecules will be denatured to single strands.
- In the second cycle, each of the single strands will anneal with a primer, and the DNA polymerase enzyme will extend the primer, creating two new DNA strands.
- In the third cycle, each of the four DNA strands will denature, creating 8 single strands.
- In the fourth cycle, each of the 8 single strands will anneal with a primer, and the DNA polymerase enzyme will extend the primer, creating 16 new DNA strands.
- In the fifth cycle, each of the 16 DNA strands will denature, creating 32 single strands.
- Each of these 32 single strands will anneal with a primer, and the DNA polymerase enzyme will extend the primer, creating 64 new DNA strands.
Therefore, the total number of DNA molecules present after 5 cycles of PCR starting with 3 molecules of template DNA is 96 to 96.
Final Answer: 96 to 96.
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Community Answer
The total number of DNA molecules present after 5 cycles of polymerase...
Formula : N=N′ × 2^n
where, N = final no. of DNA molecules
N' = intial no. of DNA molecules
so, 3× 2^5 = 3×32= 96
where, N = final no. of DNA molecules
N' = intial no. of DNA molecules
so, 3× 2^5 = 3×32= 96
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The total number of DNA molecules present after 5 cycles of polymerase chain reaction (PCR) starting with 3 molecules of template DNA is ________.Correct answer is '96 to 96'. Can you explain this answer?
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