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How many compounds (given below) shows three signals in new 13C-NMR spectrum ______ O-xylene, p-xylene, 1, 4-dimethoxybenzene, trans-1,2-dimethylcyclopropane, 4-bromoanisole, cis-1, 2 dimethylcyclopropane, Resorcinol
    Correct answer is '4'. Can you explain this answer?
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    Explanation:

    To determine the number of signals in the 13C-NMR spectrum, we need to consider the different types of carbon atoms present in each compound. Each unique chemical environment of carbon atoms will result in a distinct signal in the spectrum.

    The compounds given are:
    1. O-xylene
    2. p-xylene
    3. 1,4-dimethoxybenzene
    4. trans-1,2-dimethylcyclopropane
    5. 4-bromoanisole
    6. cis-1,2-dimethylcyclopropane
    7. Resorcinol

    O-xylene:
    - O-xylene has three different types of carbon atoms.
    - It contains a methyl group (-CH3) attached to an aromatic ring, which produces one signal.
    - It also has two aromatic carbon atoms, which are chemically equivalent and produce another signal.
    - Therefore, O-xylene shows a total of two signals in the 13C-NMR spectrum.

    p-xylene:
    - P-xylene also has three different types of carbon atoms.
    - It contains a methyl group (-CH3) attached to an aromatic ring, which produces one signal.
    - It also has two aromatic carbon atoms, which are chemically equivalent and produce another signal.
    - Therefore, p-xylene shows a total of two signals in the 13C-NMR spectrum.

    1,4-dimethoxybenzene:
    - 1,4-dimethoxybenzene has three different types of carbon atoms.
    - It contains two methoxy (-OCH3) groups attached to an aromatic ring, which produce one signal.
    - It also has one aromatic carbon atom, which produces another signal.
    - Therefore, 1,4-dimethoxybenzene shows a total of two signals in the 13C-NMR spectrum.

    trans-1,2-dimethylcyclopropane:
    - Trans-1,2-dimethylcyclopropane has four different types of carbon atoms.
    - It contains two methyl groups (-CH3), which are chemically equivalent and produce one signal.
    - It also has two different types of methylene (-CH2-) groups, which produce another two signals.
    - Therefore, trans-1,2-dimethylcyclopropane shows a total of three signals in the 13C-NMR spectrum.

    4-bromoanisole:
    - 4-bromoanisole has four different types of carbon atoms.
    - It contains a bromine atom (-Br) attached to an aromatic ring, which produces one signal.
    - It also has two methoxy (-OCH3) groups attached to an aromatic ring, which produce another one signal.
    - It has one aromatic carbon atom, which produces another signal.
    - Therefore, 4-bromoanisole shows a total of three signals in the 13C-NMR spectrum.

    cis-1,2-dimethylcyclopropane:
    - Cis-1,2-dimethylcyclopropane has four different types of carbon atoms.
    - It contains two methyl groups (-CH3), which are chemically equivalent and produce one signal.
    - It also has two different types of methylene (-CH2-) groups, which produce another two
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    How many compounds (given below) shows three signals in new 13C-NMR spectrum______ O-xylene, p-xylene,1, 4-dimethoxybenzene,trans-1,2-dimethylcyclopropane,4-bromoanisole,cis-1,2 dimethylcyclopropane,ResorcinolCorrect answer is '4'. Can you explain this answer?
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    How many compounds (given below) shows three signals in new 13C-NMR spectrum______ O-xylene, p-xylene,1, 4-dimethoxybenzene,trans-1,2-dimethylcyclopropane,4-bromoanisole,cis-1,2 dimethylcyclopropane,ResorcinolCorrect answer is '4'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about How many compounds (given below) shows three signals in new 13C-NMR spectrum______ O-xylene, p-xylene,1, 4-dimethoxybenzene,trans-1,2-dimethylcyclopropane,4-bromoanisole,cis-1,2 dimethylcyclopropane,ResorcinolCorrect answer is '4'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many compounds (given below) shows three signals in new 13C-NMR spectrum______ O-xylene, p-xylene,1, 4-dimethoxybenzene,trans-1,2-dimethylcyclopropane,4-bromoanisole,cis-1,2 dimethylcyclopropane,ResorcinolCorrect answer is '4'. Can you explain this answer?.
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