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In the 300 MHz 1H NMR spectra, an organic compound exhibit doublet. Two lines of the doublet are at δ 2.35 and δ 2.38 ppm. The coupling constant is
  • a)
    6 Hz
  • b)
    3 Hz
  • c)
    9 Hz
  • d)
    12 Hz
Correct answer is option 'C'. Can you explain this answer?
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Different chemical shifts and have equal intensities. The chemical shifts of the two lines are typically given in parts per million (ppm), which is a relative unit used to describe the position of the peak in the NMR spectrum.

For example, let's say the chemical shifts of the two lines of the doublet are at 1.2 ppm and 1.6 ppm. This means that the two signals are located at different positions along the x-axis of the NMR spectrum, with one signal appearing at 1.2 ppm and the other at 1.6 ppm.

The equal intensities of the two lines mean that the two signals have the same height or area under the peak. This indicates that the two proton environments responsible for these signals have the same number of protons and are in equivalent chemical environments.

The doublet pattern arises due to the coupling between the protons responsible for the signals and neighboring protons. In this case, the two protons responsible for the signals are coupled to each other, resulting in a splitting pattern with two lines.

The splitting pattern and chemical shifts observed in the 300 MHz 1H NMR spectra can provide valuable information about the structure and connectivity of the organic compound being analyzed.
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In the 300 MHz 1H NMR spectra, an organic compound exhibit doublet. Two lines of the doublet are atδ 2.35 andδ 2.38 ppm. The coupling constant isa)6 Hzb)3 Hzc)9 Hzd)12 HzCorrect answer is option 'C'. Can you explain this answer?
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