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The standard enthalpy of formation of NH3 is –46.0 kJ/mol. If the enthalpy of formation of H2 from its atoms is –436 kJ/mol and that of N2 is –712 kJ/mol, the average bond enthalpy of N— H bond in NH3 is :a)− 1102 kJ/molb)− 964 kJ/molc)+352 kJ/mold)+1056 kJ/molCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The standard enthalpy of formation of NH3 is –46.0 kJ/mol. If the enthalpy of formation of H2 from its atoms is –436 kJ/mol and that of N2 is –712 kJ/mol, the average bond enthalpy of N— H bond in NH3 is :a)− 1102 kJ/molb)− 964 kJ/molc)+352 kJ/mold)+1056 kJ/molCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard enthalpy of formation of NH3 is –46.0 kJ/mol. If the enthalpy of formation of H2 from its atoms is –436 kJ/mol and that of N2 is –712 kJ/mol, the average bond enthalpy of N— H bond in NH3 is :a)− 1102 kJ/molb)− 964 kJ/molc)+352 kJ/mold)+1056 kJ/molCorrect answer is option 'C'. Can you explain this answer?.

Solutions for The standard enthalpy of formation of NH3 is –46.0 kJ/mol. If the enthalpy of formation of H2 from its atoms is –436 kJ/mol and that of N2 is –712 kJ/mol, the average bond enthalpy of N— H bond in NH3 is :a)− 1102 kJ/molb)− 964 kJ/molc)+352 kJ/mold)+1056 kJ/molCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The standard enthalpy of formation of NH3 is –46.0 kJ/mol. If the enthalpy of formation of H2 from its atoms is –436 kJ/mol and that of N2 is –712 kJ/mol, the average bond enthalpy of N— H bond in NH3 is :a)− 1102 kJ/molb)− 964 kJ/molc)+352 kJ/mold)+1056 kJ/molCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The standard enthalpy of formation of NH3 is –46.0 kJ/mol. If the enthalpy of formation of H2 from its atoms is –436 kJ/mol and that of N2 is –712 kJ/mol, the average bond enthalpy of N— H bond in NH3 is :a)− 1102 kJ/molb)− 964 kJ/molc)+352 kJ/mold)+1056 kJ/molCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The standard enthalpy of formation of NH3 is –46.0 kJ/mol. If the enthalpy of formation of H2 from its atoms is –436 kJ/mol and that of N2 is –712 kJ/mol, the average bond enthalpy of N— H bond in NH3 is :a)− 1102 kJ/molb)− 964 kJ/molc)+352 kJ/mold)+1056 kJ/molCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The standard enthalpy of formation of NH3 is –46.0 kJ/mol. If the enthalpy of formation of H2 from its atoms is –436 kJ/mol and that of N2 is –712 kJ/mol, the average bond enthalpy of N— H bond in NH3 is :a)− 1102 kJ/molb)− 964 kJ/molc)+352 kJ/mold)+1056 kJ/molCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The standard enthalpy of formation of NH3 is –46.0 kJ/mol. If the enthalpy of formation of H2 from its atoms is –436 kJ/mol and that of N2 is –712 kJ/mol, the average bond enthalpy of N— H bond in NH3 is :a)− 1102 kJ/molb)− 964 kJ/molc)+352 kJ/mold)+1056 kJ/molCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.