If the base composition of A in a dsDNA molecule is 20%, the amount of...
According to Chargaff’s rule, a 1: 1 ratio of purines to pyrimidines must be present in any ds DNA.
% A = %T and %G = %C
If A = 20% and T will also be 20%. Further, 100%-40% = 60%.
Since G and C are present in equal amounts, 60/2 = 30%.
Therefore, amount of G present will be 30%.
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If the base composition of A in a dsDNA molecule is 20%, the amount of...
< b="" />Base Composition of DNA< />
The base composition of DNA refers to the relative amounts of each of the four nucleotide bases - adenine (A), guanine (G), cytosine (C), and thymine (T) - present in the DNA molecule. In a double-stranded DNA molecule, A always pairs with T, and G always pairs with C.
< b="" />Given Information< />
In this question, it is stated that the base composition of A in the dsDNA molecule is 20%. This means that 20% of the nucleotides in the DNA molecule are adenine (A).
< b="" />Calculating the Amount of G< />
Since A always pairs with T and the total amount of A is 20%, the total amount of T must also be 20%. This is because, in a double-stranded DNA molecule, the amount of A is always equal to the amount of T.
Now, the remaining 60% of the nucleotides must be made up of G and C. Since G always pairs with C, the amount of G must be equal to the amount of C in the DNA molecule.
Therefore, the total amount of G + C is 60%. Since G and C are present in equal amounts, G must be 30% of the total nucleotides in the DNA molecule.
< b="" />Final Answer< />
Hence, the amount of G (in %) present in the DNA molecule is 30%.