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If cot-1[(cos α)1/2] - tan-1[(cot α)1/2] = x, then sin x =
  • a)
    tan2α/2
  • b)
    cot2α/2
  • c)
    tan α
  • d)
    cot α/2
Correct answer is option 'B'. Can you explain this answer?
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If cot-1[(cos α)1/2] - tan-1[(cot α)1/2] = x, then sin x =...
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If cot-1[(cos α)1/2] - tan-1[(cot α)1/2] = x, then sin x =a)tan2α/2b)cot2α/2c)tan αd)cot α/2Correct answer is option 'B'. Can you explain this answer?
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