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A fruit seller has a certain number of mangoes of which 5% are rotten. He sells 75% of the remaining and he is left with 95 mangoes. How many mangoes did he have originally?
- a)500
- b)450
- c)400
- d)350
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A fruit seller has a certain number of mangoes of which 5% are rotten....
Let the original number of mangoes he had be ‘x’
Number of mangoes which were not rotten = (100 – 5)/100 × x = 0.95x
Number of mangoes unsold out of them = (100 – 75)/100 × 0.95x = 0.25 × 0.95x
⇒ 95 = 0.25 × 0.95x
⇒ 100 = 0.25x
∴ x = 400
∴ He had 400 mangoes originally
⇒ 95 = 0.25 × 0.95x
⇒ 100 = 0.25x
∴ x = 400
∴ He had 400 mangoes originally
Most Upvoted Answer
A fruit seller has a certain number of mangoes of which 5% are rotten....
Given:
- The fruit seller has a certain number of mangoes.
- 5% of the mangoes are rotten.
- The seller sells 75% of the remaining mangoes.
- After selling, the seller is left with 95 mangoes.
To find:
- The original number of mangoes the seller had.
Solution:
Let's assume the original number of mangoes the seller had is 'x'.
Step 1: Calculate the number of rotten mangoes
5% of the mangoes are rotten, so the number of rotten mangoes is 0.05x.
Step 2: Calculate the number of good mangoes
The remaining mangoes after removing the rotten ones will be (100% - 5%) = 95% of the original number of mangoes.
So, the number of good mangoes will be 0.95x.
Step 3: Calculate the number of mangoes sold
The seller sells 75% of the remaining mangoes, which means he sells 0.75 * 0.95x = 0.7125x mangoes.
Step 4: Calculate the number of mangoes left
After selling, the seller is left with 95 mangoes, so the number of mangoes left is 0.95x - 0.7125x = 0.2375x.
Step 5: Solve for x
According to the given information, 0.2375x = 95.
Simplifying, x = 95 / 0.2375 = 400.
Therefore, the fruit seller originally had 400 mangoes. Hence, the correct answer is option 'C'.
- The fruit seller has a certain number of mangoes.
- 5% of the mangoes are rotten.
- The seller sells 75% of the remaining mangoes.
- After selling, the seller is left with 95 mangoes.
To find:
- The original number of mangoes the seller had.
Solution:
Let's assume the original number of mangoes the seller had is 'x'.
Step 1: Calculate the number of rotten mangoes
5% of the mangoes are rotten, so the number of rotten mangoes is 0.05x.
Step 2: Calculate the number of good mangoes
The remaining mangoes after removing the rotten ones will be (100% - 5%) = 95% of the original number of mangoes.
So, the number of good mangoes will be 0.95x.
Step 3: Calculate the number of mangoes sold
The seller sells 75% of the remaining mangoes, which means he sells 0.75 * 0.95x = 0.7125x mangoes.
Step 4: Calculate the number of mangoes left
After selling, the seller is left with 95 mangoes, so the number of mangoes left is 0.95x - 0.7125x = 0.2375x.
Step 5: Solve for x
According to the given information, 0.2375x = 95.
Simplifying, x = 95 / 0.2375 = 400.
Therefore, the fruit seller originally had 400 mangoes. Hence, the correct answer is option 'C'.
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A fruit seller has a certain number of mangoes of which 5% are rotten....
Answer ( C ) 400
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A fruit seller has a certain number of mangoes of which 5% are rotten. He sells 75% of the remaining and he is left with 95 mangoes. How many mangoes did he have originally?a)500b)450c)400d)350Correct answer is option 'C'. Can you explain this answer?
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