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The activation energy of a reaction is 225 kcal mol^-1 and the value of rate constant at 40 degree Celsius is 1.8*10^-5.calculate the frequency factor, A.?
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The activation energy of a reaction is 225 kcal mol^-1 and the value o...
We are given value of activation energy,Ea and rate constant, k and time,t....thus by giving these values in arrehnius equation we gets log A then by taking its anti log we gets the frequency factor A
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The activation energy of a reaction is 225 kcal mol^-1 and the value o...


Calculation of Frequency Factor (A)

Given data:
Activation energy (Ea) = 225 kcal mol^-1
Temperature (T) = 40°C = 313 K
Rate constant (k) = 1.8*10^-5

Arrhenius Equation:
The Arrhenius equation is given by:
k = A * e^(-Ea/RT)
where:
k = rate constant
A = frequency factor
Ea = activation energy
R = gas constant
T = temperature in Kelvin

Calculation:
We can rearrange the Arrhenius equation to solve for the frequency factor (A):
A = k / e^(-Ea/RT)

Substitute the given values:
A = 1.8*10^-5 / e^(-225000/(1.987*313))

Calculate the value of A using the above formula.

Therefore, the frequency factor (A) for the reaction is calculated using the given rate constant and activation energy at 40°C. This factor represents the number of successful collisions per unit time and is an essential parameter in determining the rate of a chemical reaction.
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The activation energy of a reaction is 225 kcal mol^-1 and the value of rate constant at 40 degree Celsius is 1.8*10^-5.calculate the frequency factor, A.?
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