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A bob of mass m attached to an inextensible string of length l is suspended from a vertical support.
The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical. About the point of suspension
The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical. About the point of suspension
- a)Angular momentum is conserved
- b)Angular momentum changes in magnitude but not in direction
- c)Angular momentum changes in direction but not in magnitude
- d)Angular momentum changes both in direction and magnitude
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A bob of mass m attached to an inextensible string of length l is susp...
τ = mg × l sin θ. (Direction parallel to plane of rotation of particle)
as
perpendicular to 
direction of L changes but magnitude remains same.
as
perpendicular to direction of L changes but magnitude remains same.Most Upvoted Answer
A bob of mass m attached to an inextensible string of length l is susp...
Ω. The tension in the string is T. The gravitational force acting on the bob is mg, where g is the acceleration due to gravity. The centripetal force acting on the bob is mv²/l, where v is the linear velocity of the bob.
Since the bob is rotating in a horizontal circle, the gravitational force and the tension in the string provide the centripetal force needed to keep the bob moving in a circle. Therefore, we have the following equation:
mg + T = mv²/l
Simplifying this equation, we get:
T = mv²/l - mg
Since the angular speed ω is related to the linear velocity v by the equation v = ωl, we can substitute this into the equation:
T = mω²l/l - mg
T = mω² - mg
So, the tension in the string is given by T = mω² - mg.
Since the bob is rotating in a horizontal circle, the gravitational force and the tension in the string provide the centripetal force needed to keep the bob moving in a circle. Therefore, we have the following equation:
mg + T = mv²/l
Simplifying this equation, we get:
T = mv²/l - mg
Since the angular speed ω is related to the linear velocity v by the equation v = ωl, we can substitute this into the equation:
T = mω²l/l - mg
T = mω² - mg
So, the tension in the string is given by T = mω² - mg.
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A bob of mass m attached to an inextensible string of length l is suspended from a vertical support.The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical. About the point of suspensiona)Angular momentum is conservedb)Angular momentum changes in magnitude but not in directionc)Angular momentum changes in direction but not in magnituded)Angular momentum changes both in direction and magnitudeCorrect answer is option 'C'. Can you explain this answer?
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A bob of mass m attached to an inextensible string of length l is suspended from a vertical support.The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical. About the point of suspensiona)Angular momentum is conservedb)Angular momentum changes in magnitude but not in directionc)Angular momentum changes in direction but not in magnituded)Angular momentum changes both in direction and magnitudeCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bob of mass m attached to an inextensible string of length l is suspended from a vertical support.The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical. About the point of suspensiona)Angular momentum is conservedb)Angular momentum changes in magnitude but not in directionc)Angular momentum changes in direction but not in magnituded)Angular momentum changes both in direction and magnitudeCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bob of mass m attached to an inextensible string of length l is suspended from a vertical support.The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical. About the point of suspensiona)Angular momentum is conservedb)Angular momentum changes in magnitude but not in directionc)Angular momentum changes in direction but not in magnituded)Angular momentum changes both in direction and magnitudeCorrect answer is option 'C'. Can you explain this answer?.
A bob of mass m attached to an inextensible string of length l is suspended from a vertical support.The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical. About the point of suspensiona)Angular momentum is conservedb)Angular momentum changes in magnitude but not in directionc)Angular momentum changes in direction but not in magnituded)Angular momentum changes both in direction and magnitudeCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bob of mass m attached to an inextensible string of length l is suspended from a vertical support.The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical. About the point of suspensiona)Angular momentum is conservedb)Angular momentum changes in magnitude but not in directionc)Angular momentum changes in direction but not in magnituded)Angular momentum changes both in direction and magnitudeCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bob of mass m attached to an inextensible string of length l is suspended from a vertical support.The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical. About the point of suspensiona)Angular momentum is conservedb)Angular momentum changes in magnitude but not in directionc)Angular momentum changes in direction but not in magnituded)Angular momentum changes both in direction and magnitudeCorrect answer is option 'C'. Can you explain this answer?.
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